Radius is 10 cm. (i) Minor sector area is (90/360) x 3.14 x 10² = (1/4) x 314 = 78.5 cm². (ii) Major sector area is (270/360) x 3.14 x 10² = (3/4) x 314 = 235.5 cm².
Discussion Forum Latest Questions
In 60 minutes, the minute hand turns 360°, so in 10 minutes it turns (360/60) x 10 = 60°. The area swept is a sector: (60/360) x (22/7) x 7² = 77/3 = 25.67 cm².
Circumference 2 x (22/7) x r = 44 yields radius r = 7 cm. A quadrant has angle 90°, so its area is (1/4) x π x r² = (1/4) x (22/7) x 7² = 77/2 = 38.5 cm².
Using sector area formula (θ / 360) x π x r² with r = 7 cm and θ = 60° gives (60 / 360) x (22/7) x 7² = (1/6) x 154 = 77/3 = 25.67 cm².
Since CQ || PD, triangles DPQ and DPC share base PD and parallel lines, giving Area(ΔDPQ) = Area(ΔDPC). Thus, Area(ΔBPQ) = Area(ΔBPD) + Area(ΔDPQ) = Area(ΔBPD) + Area(ΔDPC) = Area(ΔBDC) = (1/2) x Area(ΔABC).