The equation is w = 3d. For a distance of d = 2 units, substituting it into the linear equation gives the work done as w = 3(2) = 6 units. Plotting (2, 6) confirms this on the graph.
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The total savings pattern is given by y = 800 + 250m, where m is the months. After 6 months, you have 2300 rupees. After 2 years (24 months), you have 6800 rupees.
Let the unknown number be x. The problem gives the linear equation 5/2 x + 2/3 = -7/12. Shifting 2/3 over gives 5/2 x = -15/12, which simplifies to the final number x = -1/2.
Form two equations from the gym data: 800 = 10a + b and 1100 = 15a + b. Subtracting them eliminates b to give 5a = 300, which means a = 60. Then, b equals 200.
A polynomial of degree 1 can be 3x plus 2. A polynomial of degree 2 can be x square plus 5x plus 1. A polynomial of degree 3 can be 2x cube minus x plus 4.