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Factor completely 4s square + 20st + 25t square
We look at the structure of the polynomial to find its factors. The first term 4s square is the square of 2s, and the final term 25t square is the square of 5t. The middle term 20st is exactly equal to two multiplied by 2s multiplied by 5t. This allows us to use the regular addition square identity,Read more
We look at the structure of the polynomial to find its factors. The first term 4s square is the square of 2s, and the final term 25t square is the square of 5t. The middle term 20st is exactly equal to two multiplied by 2s multiplied by 5t. This allows us to use the regular addition square identity, giving us a clean and complete factorization of (2s + 5t) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See lessFactor completely 49x square + 28xy + 4y square
This algebraic expression can be factored by identifying the perfect square components within it. The first part of the expression is 49x square, which is equal to (7x) square. The last part of the expression is 4y square, which is equal to (2y) square. The middle value 28xy is two times 7x times 2yRead more
This algebraic expression can be factored by identifying the perfect square components within it. The first part of the expression is 49x square, which is equal to (7x) square. The last part of the expression is 4y square, which is equal to (2y) square. The middle value 28xy is two times 7x times 2y. This fits the identity perfectly, resulting in the final answer of (7x + 2y) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See lessFactor completely 64p square + 32/3 pq + 4/9 q square
To factor this fractional expression, we examine the first and third terms. The first term 64p square is a perfect square of 8p. The third term 4/9 q square is a perfect square of 2/3 q. Checking the middle term, two times 8p times 2/3 q equals 32/3 pq. Since it matches the template completely, it fRead more
To factor this fractional expression, we examine the first and third terms. The first term 64p square is a perfect square of 8p. The third term 4/9 q square is a perfect square of 2/3 q. Checking the middle term, two times 8p times 2/3 q equals 32/3 pq. Since it matches the template completely, it forms the perfect square binomial factor (8p + 2/3 q) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See lessFactor completely 3a square + 4ab + 4/3 b square
For this problem, we take out a fractional common factor to make the terms perfect integers. Factoring out 1/3 transforms the expression into 1/3 times the quantity 9a square + 12ab + 4b square. Inside the brackets, 9a square is the square of 3a, and 4b square is the square of 2b. The middle term isRead more
For this problem, we take out a fractional common factor to make the terms perfect integers. Factoring out 1/3 transforms the expression into 1/3 times the quantity 9a square + 12ab + 4b square. Inside the brackets, 9a square is the square of 3a, and 4b square is the square of 2b. The middle term is two times 3a times 2b. This simplifies perfectly to 1/3 times (3a + 2b) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See lessFactor completely 9/5 s square + 6sv + 5v square
We simplify this factorization by removing 1/5 as a common factor first. This leaves us with 1/5 multiplied by the expression 9s square + 30sv + 25v square. Now we can easily see that 9s square is the square of 3s, and 25v square is the square of 5v. The middle term matches two times 3s times 5v. ThRead more
We simplify this factorization by removing 1/5 as a common factor first. This leaves us with 1/5 multiplied by the expression 9s square + 30sv + 25v square. Now we can easily see that 9s square is the square of 3s, and 25v square is the square of 5v. The middle term matches two times 3s times 5v. The fully factored final form is 1/5 times (3s + 5v) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
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