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Suppose List 1 and List 2 are two lists of numbers in increasing order. Write an algorithm to find elements in List 2 that are not present in List 1.
Initialize an empty list named unique-to-List2. For each element y in List 2: Scan List 1 to see whether y exists in List 1. If y does not appear in List 1, append y to unique-to-List2. (Because the lists are in increasing order, stop searching once values in List 1 exceed y.) Report unique-to-List2Read more
Scan List 1 to see whether y exists in List 1.
If y does not appear in List 1, append y to unique-to-List2.
(Because the lists are in increasing order, stop searching once values in List 1 exceed y.)
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 11 The World of Algorithms Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-11/
See lessSuppose List 1 and List 2 are two lists of numbers in increasing order. Write an algorithm to find elements in List 1 that are not present in List 2.
Initialize an empty list called unique-to-List1. For each number x in List 1: Check if x is present in List 2. If x is not present in List 2, add x to unique-to-List1. (Since both lists are sorted, you can stop checking List 2 as soon as an element exceeds x.) Report unique-to-List1. For moreRead more
Check if x is present in List 2.
If x is not present in List 2, add x to unique-to-List1.
(Since both lists are sorted, you can stop checking List 2 as soon as an element exceeds x.)
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 11 The World of Algorithms Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-11/
See lessIf n and n + 3 have no factors in common, then n is not a multiple of 3 (where n is a positive integer).
Both the proposition and its converse ("If n is not a multiple of 3, then n and n + 3 have no factors in common") are true. Any common factor of n and n + 3 must divide their difference, (n + 3) - n = 3. Hence, 3 is the only possible common prime divisor. Thus, they share common factors if and onlyRead more
Both the proposition and its converse (“If n is not a multiple of 3, then n and n + 3 have no factors in common”) are true. Any common factor of n and n + 3 must divide their difference, (n + 3) – n = 3. Hence, 3 is the only possible common prime divisor. Thus, they share common factors if and only if n is a multiple of 3.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 9 Propositions and their Converses Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-9/
See lessIf n is a product of two unequal prime numbers, then it has exactly 4 divisors (where n is a positive integer).
The proposition is true because n = pq (where p ≠ q are primes) has divisors 1, p, q and pq. However, the converse—"If n has exactly 4 divisors, then it is a product of two unequal prime numbers"—is false. As a counterexample, n = 8 = 2³ has exactly 4 divisors (1, 2, 4, 8), but 8 is a prime cube, noRead more
The proposition is true because n = pq (where p ≠ q are primes) has divisors 1, p, q and pq. However, the converse—”If n has exactly 4 divisors, then it is a product of two unequal prime numbers”—is false. As a counterexample, n = 8 = 2³ has exactly 4 divisors (1, 2, 4, 8), but 8 is a prime cube, not a product of two unequal primes.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 9 Propositions and their Converses Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-9/
See lessIf n is the square of a prime number, then it has exactly 3 factors (where n is a positive integer).
Both the proposition and its converse ("If n has exactly 3 factors, then it is the square of a prime number") are true. If n = p² for a prime p, its only divisors are 1, p and p². Conversely, a number with an odd factor count is a perfect square and having exactly 3 factors forces its prime factorizRead more
Both the proposition and its converse (“If n has exactly 3 factors, then it is the square of a prime number”) are true. If n = p² for a prime p, its only divisors are 1, p and p². Conversely, a number with an odd factor count is a perfect square and having exactly 3 factors forces its prime factorization to be p².
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 9 Propositions and their Converses Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-9/
See less