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Factor using suitable identities: p square/16 – 2 + 16/p square
We factor this variable fraction expression by recognizing the underlying square identity. The first term is the square of p/4, and the final term 16/p square is the square of 4/p. The middle term is negative, and when we calculate two times p/4 times 4/p, the variables cancel out perfectly to leaveRead more
We factor this variable fraction expression by recognizing the underlying square identity. The first term is the square of p/4, and the final term 16/p square is the square of 4/p. The middle term is negative, and when we calculate two times p/4 times 4/p, the variables cancel out perfectly to leave just the number two. This gives us the final factored expression (p/4 – 4/p) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See lessFactor using suitable identities: m square/9 + mk/3 + k square/4 + 3nk + 2mn + 9n square
We observe that this long expression has six separate terms, which indicates it comes from a three-term square identity. The three perfect square terms are m square/9, k square/4 and 9n square, which are the squares of m/3, k/2 and 3n respectively. The remaining three terms perfectly match the doublRead more
We observe that this long expression has six separate terms, which indicates it comes from a three-term square identity. The three perfect square terms are m square/9, k square/4 and 9n square, which are the squares of m/3, k/2 and 3n respectively. The remaining three terms perfectly match the double cross-products of these bases. Therefore, the complete factored form is (m/3 + k/2 + 3n) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See lessFactor completely 4s square + 20st + 25t square
We look at the structure of the polynomial to find its factors. The first term 4s square is the square of 2s, and the final term 25t square is the square of 5t. The middle term 20st is exactly equal to two multiplied by 2s multiplied by 5t. This allows us to use the regular addition square identity,Read more
We look at the structure of the polynomial to find its factors. The first term 4s square is the square of 2s, and the final term 25t square is the square of 5t. The middle term 20st is exactly equal to two multiplied by 2s multiplied by 5t. This allows us to use the regular addition square identity, giving us a clean and complete factorization of (2s + 5t) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See lessFactor completely 49x square + 28xy + 4y square
This algebraic expression can be factored by identifying the perfect square components within it. The first part of the expression is 49x square, which is equal to (7x) square. The last part of the expression is 4y square, which is equal to (2y) square. The middle value 28xy is two times 7x times 2yRead more
This algebraic expression can be factored by identifying the perfect square components within it. The first part of the expression is 49x square, which is equal to (7x) square. The last part of the expression is 4y square, which is equal to (2y) square. The middle value 28xy is two times 7x times 2y. This fits the identity perfectly, resulting in the final answer of (7x + 2y) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See lessFactor completely 64p square + 32/3 pq + 4/9 q square
To factor this fractional expression, we examine the first and third terms. The first term 64p square is a perfect square of 8p. The third term 4/9 q square is a perfect square of 2/3 q. Checking the middle term, two times 8p times 2/3 q equals 32/3 pq. Since it matches the template completely, it fRead more
To factor this fractional expression, we examine the first and third terms. The first term 64p square is a perfect square of 8p. The third term 4/9 q square is a perfect square of 2/3 q. Checking the middle term, two times 8p times 2/3 q equals 32/3 pq. Since it matches the template completely, it forms the perfect square binomial factor (8p + 2/3 q) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
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