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How is it different from the algebraic expression in Example 1?
The algebraic expression in Example 1 is 4x + 5y + 3, where the variables x and y appear separately in different terms. In Example 2, the expression is 200l + 160w + 50lw. The important difference is that the term 50lw contains two variables multiplied together. Example 1 includes a constant term 3,Read more
The algebraic expression in Example 1 is 4x + 5y + 3, where the variables x and y appear separately in different terms. In Example 2, the expression is 200l + 160w + 50lw. The important difference is that the term 50lw contains two variables multiplied together. Example 1 includes a constant term 3, but Example 2 has no constant term. Also, Example 1 is about counting pens and pencils, while Example 2 is related to the cost of fencing and seeds.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessA wire of length 20 cm is bent in different ways to form rectangles. For example, we can have a rectangle with length 7 cm and width 3 cm. We can also have one of length 5.5 cm and width 4.5 cm. (Think of a few more ways of forming such rectangles.) Can you write an expression for the area of such rectangles?
The total length of the wire is 20 cm, so the perimeter of the rectangle is 20 cm. Since the perimeter formula is 2 multiplied by length plus width, the sum of length and width becomes 10 cm. If the length is x cm, then the width will be 10 minus x cm. The area of a rectangle is length multiplied byRead more
The total length of the wire is 20 cm, so the perimeter of the rectangle is 20 cm. Since the perimeter formula is 2 multiplied by length plus width, the sum of length and width becomes 10 cm. If the length is x cm, then the width will be 10 minus x cm. The area of a rectangle is length multiplied by width. Therefore, the expression for the area of the rectangle is x multiplied by 10 minus x or 10x minus x square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessWrite polynomials of degrees 1, 2 and 3.
The degree of a polynomial depends on the highest power of the variable. A polynomial of degree 1 is called a linear polynomial, such as 3x plus 2. A polynomial of degree 2 is called a quadratic polynomial, such as x square plus 5x plus 1. A polynomial of degree 3 is called a cubic polynomial, suchRead more
The degree of a polynomial depends on the highest power of the variable. A polynomial of degree 1 is called a linear polynomial, such as 3x plus 2. A polynomial of degree 2 is called a quadratic polynomial, such as x square plus 5x plus 1. A polynomial of degree 3 is called a cubic polynomial, such as 2x cube minus x plus 4. In each case, the highest power of x determines the degree of the polynomial.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessA rectangular garden of length l metres and width w metres has to be fenced and decorated. A wire fence is to be laid along the length costing rupees 100 per metre and a wooden fence is to be built along the width costing rupees 80 per metre. Special seeds have to be sown throughout the garden which will cost rupees 50 per square metre.
For the rectangular garden, wire fencing is needed along the length and wooden fencing along the width. Since the garden has two lengths and two widths, the wire fencing cost becomes 200l rupees and the wooden fencing cost becomes 160w rupees. The area of the garden is lw square metres, so the seedRead more
For the rectangular garden, wire fencing is needed along the length and wooden fencing along the width. Since the garden has two lengths and two widths, the wire fencing cost becomes 200l rupees and the wooden fencing cost becomes 160w rupees. The area of the garden is lw square metres, so the seed cost becomes 50lw rupees. By adding all these costs together, we get the algebraic expression for the total cost as 200l + 160w + 50lw.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See lessFind the perimeter of squares with sides 1 cm, 1.5 cm, 2 cm, 2.5 cm and 3 cm. What will happen to the perimeters if the sides increase by 0.5 cm?
The perimeter of a square is found by multiplying the side by 4. Therefore, for sides 1 cm, 1.5 cm, 2 cm, 2.5 cm and 3 cm, the perimeters are 4 cm, 6 cm, 8 cm, 10 cm and 12 cm respectively. We observe that every time the side increases by 0.5 cm, the perimeter increases by 2 cm. This increase is conRead more
The perimeter of a square is found by multiplying the side by 4. Therefore, for sides 1 cm, 1.5 cm, 2 cm, 2.5 cm and 3 cm, the perimeters are 4 cm, 6 cm, 8 cm, 10 cm and 12 cm respectively. We observe that every time the side increases by 0.5 cm, the perimeter increases by 2 cm. This increase is constant, so the pattern formed is called a linear pattern.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/
See less