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The government levies higher taxes on products such as tobacco and alcohol to promote healthier choices among citizens. Can you find out other goods where price controls have been set in place? What are the reasons for the same?
Governments enforce price controls on life-saving medicines, hospital equipment, baby food and hand sanitisers under essential commodity regulations to prevent black-marketing and ensure affordability for vulnerable citizens. Additionally, price floors such as minimum support prices for wheat and paRead more
Governments enforce price controls on life-saving medicines, hospital equipment, baby food and hand sanitisers under essential commodity regulations to prevent black-marketing and ensure affordability for vulnerable citizens. Additionally, price floors such as minimum support prices for wheat and paddy ensure farmers receive fair remuneration. These interventions aim to maintain social equity, public health, food security and market transparency during crises.
For more NCERT Solutions of Class 9 Social Science Chapter 9 The Price Puzzle What Drives the Market Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/social-science/
See lessCan excessive government regulation hurt markets? Explain with suitable examples.
Excessive government intervention harms economic growth by distorting price signals and lowering producer incentives. For example, capping crop prices below actual farming costs discourages farmers from expanding production, resulting in agricultural deficits. Moreover, heavy compliance burdens invoRead more
Excessive government intervention harms economic growth by distorting price signals and lowering producer incentives. For example, capping crop prices below actual farming costs discourages farmers from expanding production, resulting in agricultural deficits. Moreover, heavy compliance burdens involving multiple permits, safety inspections and clearance certificates increase operating costs for small enterprises, diminishing the ease of doing business and discouraging technological innovation and entrepreneurship.
For more NCERT Solutions of Class 9 Social Science Chapter 9 The Price Puzzle What Drives the Market Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/social-science/
See lessA car has two wipers which do not overlap. Each wiper has a blade of length 28 cm and sweeps through an angle of 120°. Find the total area cleaned at each sweep of the blades.
Given blade length r = 28 cm, angle of sweep θ = 120° and number of wipers = 2. Area swept by one wiper blade: Area = (θ / 360) x π x r² Area = (120 / 360) x (22/7) x 28 x 28 Area = (1/3) x 22 x 4 x 28 = 2464 / 3 cm². Total area cleaned by both wipers: Total Area = 2 x (2464 / 3) = 4928 / 3 cm². InRead more
Given blade length r = 28 cm, angle of sweep θ = 120° and number of wipers = 2.
Area swept by one wiper blade:
Area = (θ / 360) x π x r²
Area = (120 / 360) x (22/7) x 28 x 28
Area = (1/3) x 22 x 4 x 28 = 2464 / 3 cm².
Total area cleaned by both wipers:
Total Area = 2 x (2464 / 3) = 4928 / 3 cm².
In decimal form, 4928 / 3 is approximately 1642.67 cm².
Thus, total area cleaned is 4928/3 cm² (or 1642.67 cm²).
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/
See lessA chord of a circle of radius 15 cm subtends an angle of 60° at the centre of the circle. Find the areas of the corresponding minor and major segments of the circle. (Use π ≈ 3.14 and √3 ≈ 1.73.)
Given r = 15 cm, θ = 60°, π = 3.14 and √3 = 1.73. Total circle area = π x r² = 3.14 x 15² = 3.14 x 225 = 706.5 cm². Area of minor sector = (60 / 360) x 3.14 x 225 = (1/6) x 706.5 = 117.75 cm². The triangle formed is equilateral (angle 60°): Area of triangle = (√3 / 4) x r² = (1.73 / 4) x 225 = 97.31Read more
Given r = 15 cm, θ = 60°, π = 3.14 and √3 = 1.73.
Total circle area = π x r² = 3.14 x 15² = 3.14 x 225 = 706.5 cm².
Area of minor sector = (60 / 360) x 3.14 x 225 = (1/6) x 706.5 = 117.75 cm².
The triangle formed is equilateral (angle 60°):
Area of triangle = (√3 / 4) x r² = (1.73 / 4) x 225 = 97.3125 cm².
Minor segment = Minor sector – Triangle = 117.75 – 97.3125 = 20.4375 cm² (or 20.44 cm²).
Major segment = Circle area – Minor segment = 706.5 – 20.4375 = 686.0625 cm² (or 686.06 cm²).
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/
See lessA chord of a circle of radius 10 cm subtends 90° at the centre. Find the area of the corresponding: (i) minor sector (that subtends 90° at the centre) and (ii) major sector (that subtends 270° at the centre). (Use π ≈ 3.14.)
Given radius r = 10 cm and π = 3.14. Total area of the circle = π x r² = 3.14 x 10² = 314 cm². (i) For the minor sector, angle θ = 90°: Area = (90 / 360) x π x r² = (1/4) x 314 = 78.5 cm². (ii) For the major sector, angle θ = 360° - 90° = 270°: Area = (270 / 360) x π x r² = (3/4) x 314 = 235.5 cm² (Read more
Given radius r = 10 cm and π = 3.14.
Total area of the circle = π x r² = 3.14 x 10² = 314 cm².
(i) For the minor sector, angle θ = 90°:
Area = (90 / 360) x π x r² = (1/4) x 314 = 78.5 cm².
(ii) For the major sector, angle θ = 360° – 90° = 270°:
Area = (270 / 360) x π x r² = (3/4) x 314 = 235.5 cm²
(or Total Area – Minor Sector Area = 314 – 78.5 = 235.5 cm²).
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/
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