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Consider the graph of the equation 3x – 7y = 21 shown below. Does the point C (2, 3) lie on the line? Does it satisfy the equation? Can points that do not lie on the line satisfy the equation?
Point C (2, 3) clearly does not lie on the graphed line. Substituting x = 2 and y = 3 gives LHS = 3(2) - 7(3) = 6 - 21 = -15, which does not equal 21 (RHS). Therefore, it does not satisfy the equation. Geometrically, every solution corresponds strictly to a point on the line; hence, points not lyingRead more
Point C (2, 3) clearly does not lie on the graphed line. Substituting x = 2 and y = 3 gives LHS = 3(2) – 7(3) = 6 – 21 = -15, which does not equal 21 (RHS). Therefore, it does not satisfy the equation. Geometrically, every solution corresponds strictly to a point on the line; hence, points not lying on the line cannot satisfy the equation.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See lessFind two solutions which lie in different quadrants for the linear equation -5x – 3y = 7 and identify the quadrants.
Setting x = -2 in -5x - 3y = 7 gives 10 - 3y = 7, which simplifies to -3y = -3, yielding y = 1. The resulting point (-2, 1) lies in Quadrant II. Setting x = 1 produces -5 - 3y = 7, which simplifies to -3y = 12, yielding y = -4. The resulting point (1, -4) lies in Quadrant IV. For more NCERT SRead more
Setting x = -2 in -5x – 3y = 7 gives 10 – 3y = 7, which simplifies to -3y = -3, yielding y = 1. The resulting point (-2, 1) lies in Quadrant II. Setting x = 1 produces -5 – 3y = 7, which simplifies to -3y = 12, yielding y = -4. The resulting point (1, -4) lies in Quadrant IV.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See lessFind two solutions which lie in different quadrants for the linear equation -5x + 3y = 7 and identify the quadrants.
Substituting x = 1 into -5x + 3y = 7 produces -5 + 3y = 7, which simplifies to 3y = 12, giving y = 4. This corresponds to (1, 4) in Quadrant I. Substituting x = -2 gives 10 + 3y = 7, which simplifies to 3y = -3, yielding y = -1. This corresponds to the point (-2, -1) located in Quadrant III. Read more
Substituting x = 1 into -5x + 3y = 7 produces -5 + 3y = 7, which simplifies to 3y = 12, giving y = 4. This corresponds to (1, 4) in Quadrant I. Substituting x = -2 gives 10 + 3y = 7, which simplifies to 3y = -3, yielding y = -1. This corresponds to the point (-2, -1) located in Quadrant III.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See lessFind two solutions which lie in different quadrants for the linear equation 5x – 3y = 7 and identify the quadrants.
Substituting x = 2 into 5x - 3y = 7 gives 10 - 3y = 7, leading to -3y = -3, so y = 1. The point (2, 1) lies in Quadrant I. Substituting x = -1 yields -5 - 3y = 7, leading to -3y = 12, so y = -4. The point (-1, -4) lies in Quadrant III. For more NCERT Solutions of Class 9 Maths Ganita ManjariRead more
Substituting x = 2 into 5x – 3y = 7 gives 10 – 3y = 7, leading to -3y = -3, so y = 1. The point (2, 1) lies in Quadrant I. Substituting x = -1 yields -5 – 3y = 7, leading to -3y = 12, so y = -4. The point (-1, -4) lies in Quadrant III.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
See lessFind two solutions which lie in different quadrants for the linear equation 5x + 3y = 7 and identify the quadrants.
Choosing x = 2 yields 5(2) + 3y = 7, which simplifies to 3y = -3, giving y = -1. This solution represents the point (2, -1) located in Quadrant IV. Choosing x = -1 gives 5(-1) + 3y = 7, simplifying to 3y = 12, giving y = 4. This solution is the point (-1, 4), which lies in Quadrant II. For moRead more
Choosing x = 2 yields 5(2) + 3y = 7, which simplifies to 3y = -3, giving y = -1. This solution represents the point (2, -1) located in Quadrant IV. Choosing x = -1 gives 5(-1) + 3y = 7, simplifying to 3y = 12, giving y = 4. This solution is the point (-1, 4), which lies in Quadrant II.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/
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