Total opposing force is 7 N plus 3 N, totaling 10 N, producing a deceleration of 5 m s-2 on the 2 kg mass. Using kinematics, the stopping distance traveled before coming to rest is 10 meters.
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Converting 108 km h-1 gives 30 m s-1. The change in momentum is 0.4 kg multiplied by 30 m s-1, which equals 12 kg m s-1. Dividing by 800 N force gives 0.015 seconds contact time.
The minor sector area is (60/360) x π x r² = (1/6)πr². The triangle formed is equilateral with side r, giving area (√3/4)r². Subtracting yields segment area (1/6)πr² – (√3/4)r² = πr²(1/6 – √3/(4π)).
One blade cleans a sector of radius 28 cm and angle 120°: (120/360) x (22/7) x 28² = 2464/3 cm². With two blades, total cleaned area is 2 x (2464/3) = 4928/3 = 1642.67 cm².
Minor sector is (60/360) x 3.14 x 15² = 117.75 cm². Equilateral triangle area is (√3/4) x 15² = 97.31 cm². Minor segment is 117.75 – 97.31 = 20.44 cm². Major segment is 706.5 – 20.44 = 686.06 cm².