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Using the identity (a – b) square = a square – 2ab + b square, find the value of (79) square
To calculate this square easily without direct vertical multiplication, we express 79 as 80 - 1. This lets us use the subtraction square identity where a is 80 and b is 1. The square of 80 is 6400, and the square of 1 is 1. The middle term to subtract is two times 80 times 1, which is 160. ComputingRead more
To calculate this square easily without direct vertical multiplication, we express 79 as 80 – 1. This lets us use the subtraction square identity where a is 80 and b is 1. The square of 80 is 6400, and the square of 1 is 1. The middle term to subtract is two times 80 times 1, which is 160. Computing 6400 minus 160 plus 1 gives 6241.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See lessUsing the identity (a – b) square = a square – 2ab + b square, find the value of (193) square
We find the value by breaking 193 down into the expression 200 - 7. Using our identity, we assign a to be 200 and b to be 7. The square of 200 results in 40000, and the square of 7 is 49. The cross-product term to subtract is calculated as two multiplied by 200 multiplied by 7, which equals 2800. SuRead more
We find the value by breaking 193 down into the expression 200 – 7. Using our identity, we assign a to be 200 and b to be 7. The square of 200 results in 40000, and the square of 7 is 49. The cross-product term to subtract is calculated as two multiplied by 200 multiplied by 7, which equals 2800. Subtracting 2800 from 40000 and adding 49 yields 37249.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See lessFind the square of 117 using a suitable identity
To calculate the square of 117 efficiently, we split the number into three manageable parts: 100 + 10 + 7. This allows us to use the algebraic identity for a three-term addition square, where a equals 100, b equals 10, and c equals 7. We find the squares of these numbers, which are 10000, 100, and 4Read more
To calculate the square of 117 efficiently, we split the number into three manageable parts: 100 + 10 + 7. This allows us to use the algebraic identity for a three-term addition square, where a equals 100, b equals 10, and c equals 7. We find the squares of these numbers, which are 10000, 100, and 49. Adding these to the cross-product terms 2000, 1400, and 140 results in 13689.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See lessFind the square of 78 using a suitable identity
We evaluate this calculation by changing the number 78 into the expression 80 - 2. This lets us use the standard subtraction square identity where a is set to 80 and b is set to 2. The square of 80 is 6400, and the square of 2 is 4. The product term to subtract is two multiplied by 80 multiplied byRead more
We evaluate this calculation by changing the number 78 into the expression 80 – 2. This lets us use the standard subtraction square identity where a is set to 80 and b is set to 2. The square of 80 is 6400, and the square of 2 is 4. The product term to subtract is two multiplied by 80 multiplied by 2, which is 320. Computing 6400 minus 320 plus 4 yields 6084.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See lessFind the square of 198 using a suitable identity
To find this square value quickly, we convert 198 into 200 - 2. We apply the identity by substituting the values where a equals 200 and b equals 2. Squaring the first term gives 40000, and squaring the second term gives 4. The intermediate term to subtract is calculated as two times 200 times 2, whiRead more
To find this square value quickly, we convert 198 into 200 – 2. We apply the identity by substituting the values where a equals 200 and b equals 2. Squaring the first term gives 40000, and squaring the second term gives 4. The intermediate term to subtract is calculated as two times 200 times 2, which equals 800. Subtracting 800 from 40000 and adding 4 results in 39204.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/
See less