Let the fraction be x/y. The equations are (x+2)/(y+2) = 9/11 and (x+3)/(y+3) = 5/6, simplifying to 11x – 9y = -4 and 6x – 5y = -3. Solving gives x = 7 and y = 9, making the fraction ...
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Piyush365
Asked: In: Class 9 Maths
Let fixed charge be ₹x and per km charge ₹y. Then x + 10y = 155 and x + 15y = 220. Subtracting gives 5y = 65, so y = 13 and x = 25. For 25 km, cost is ...
charges in a city consist of a fixed charge togetherganita manjari part 2 chapter 13 question answerganita manjari part 2 chapter 13 two variablesone line solutionsone line solutions – ganita manjari part ii chapter 13total amount paid is ₹155 and for a journey of 15 kmtwo variableswhat is the fixed charge and the charge per km
Piyush365
Asked: In: Class 9 Maths
Letting bat cost ₹x and ball ₹y gives 7x + 6y = 8880 and 3x + 5y = 4000. Multiplying and eliminating yields 17x = 20400, so x = 1200 and y = 80. A bat costs ₹1200, a ball ...
Piyush365
Asked: In: Class 9 Maths
Let the numbers be x and y with x > y. The equations are x – y = 26 and x = 3y. Substituting gives 3y – y = 26, so 2y = 26, y = 13 and x = ...
Piyush365
Asked: In: Class 9 Maths
Let the integers be x and y. Then x + y = 5 and x – y = -21. Adding both equations gives 2x = -16, so x = -8. Substituting yields y = 13. The numbers are -8 and ...