Let the tens digit be x and units digit be x – 3. The number is 11x – 3. Interchanging digits gives 11x – 30. Adding them, 22x – 33 = 143, solving to x = 8. The numbers are 85 and 58.
The digits of a two-digit number differ by 3. If the digits are interchanged and the resulting number is added to the original number, we get 143. Find both the numbers.
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Let the digits be x and y. Since they differ by 3, we can assume y = x – 3. The original two-digit number is 10x + y, which simplifies to 11x – 3. Interchanging the digits creates the new number 10y + x, which simplifies to 11x – 30. Adding these two expressions gives (11x – 3) + (11x – 30) = 143. This reduces to 22x – 33 = 143, meaning 22x = 176, so x = 8. The numbers are 85 and 58.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/