Jagannath Dixit
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A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm².

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NCERT Solutions for Class 9 Maths Chapter 13
Important NCERT Questions
Surface Areas and Volumes
NCERT Books for Session 2022-2023
CBSE Board, UP Board and Other state Boards
EXERCISE 13.4
Page No:225
Questions No:5

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2 Answers

  1. Get Hindi Medium and English Medium NCERT Solution for Class 9 Maths to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/chapter-13/

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  2. Internal radius of hemispherical bowl r = 10.5/2 = 5.25 cm
    Inner surface area of hemispherical bowl = 2πr²
    = 2 × 22/7 × 5.25 × 5.25
    = 2 × 22 × 0.75 × 5.25
    = 173.25 cm²
    Cost of tin-plating the rate of Rs 16 per 100 cm²
    = Rs 173. 25 × 16/100 = Rs 27.72
    Hence, the cost of tin- plating inside at the rate of Rs 16 per 100 cm² is Rs 27.72.

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