Using perimeter formula 2 x π x r = 44 with π = 22/7, we get 2 x (22/7) x r = 44. Dividing both sides by 44/7 gives radius r = 7 cm.
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Rectangle area is 3 x 2 = 6 m². With diameter 1 m, circle radius is 0.5 m, so circle area is π x (0.5)² = π / 4 m². The landing probability is (π / 4) / 6 = ...
List (iv) {0, 1, 2, 3} is the correct sample space because three tossed coins can yield 0, 1, 2 or 3 heads. The other lists either omit possible outcomes or include an impossible outcome.
A coin has outcomes {H, T} and the cards have numbers {1, 2, 3, 4, 5, 6}. The complete sample space consists of 12 pairs: S = {(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, ...
With replacement, tree branches into 4 paths then 4 paths each, creating 16 pairs (size 16). Without replacement, first draw branches into 4 paths then 3 paths each, creating 12 pairs (size 12).