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Kriti
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Asked: 2026-10-14T05:53:58+00:00 In:

If 20 compressions pass a point in 4 seconds, the frequency is (i) 80 Hz (ii) 5 Hz (iii) 10 Hz (iv) 0.2 Hz

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The correct option is (ii). Frequency equals total oscillations divided by time taken. Dividing 20 compressions by 4 seconds yields 5 oscillations per second, which equals 5 Hz.

Chapter 10 Sound Waves Characteristics and Applications Solutions
Sound Waves Characteristics and Applications Exercise Solutions

20 compressions pass a pointclass 9 science exploration sound waves solutions with pdfsound waves: characteristics and applications question answerthe frequency is
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    1. The correct option is (ii) 5 Hz. The frequency of a periodic wave is calculated by dividing the total number of complete oscillations or passing compressions by the total time taken. Here, dividing 20 compressions by 4 seconds gives 5 oscillations per second. Since one cycle per second equals one hertz, the wave frequency is 5 Hz.

       

      For more NCERT Solutions of Class 9 Science Exploration Chapter 10 Sound Waves Characteristics and Applications Question Answer (2026-27)

      https://www.tiwariacademy.com/ncert-solutions/class-9/science/exploration-chapter-10/

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