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Kriti
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The minor sector area is (60/360) x π x r² = (1/6)πr². The triangle formed is equilateral with side r, giving area (√3/4)r². Subtracting yields segment area (1/6)πr² – (√3/4)r² = πr²(1/6 – √3/(4π)).

chord of a circle of radius r subtends an angle of 60°corresponding minor segment of the circle is equalganita manjari class 9 exercise 6.3 solutionsncert class 9 ganita manjari chapter 6 question answersolutions - measuring space: perimeter and area
Kriti
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Radius is 10 cm. (i) Minor sector area is (90/360) x 3.14 x 10² = (1/4) x 314 = 78.5 cm². (ii) Major sector area is (270/360) x 3.14 x 10² = (3/4) x 314 = 235.5 cm².

cbse class 9 ganita manjari chapter 6 solutionschord of a circle of radius 10 cm subtends 90°ganita manjari class 9 exercise 6.3 solutionsminor sector (that subtends 90° at the centre) andncert solutions – measuring space: perimeter and area
Kriti
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Let square side be s. The sum of heights to AB and CD equals s, so Area(ΔPAB) + Area(ΔPCD) = (1/2) x s x s = s²/2. Both regions equal half the square’s area, making their ratio 1:1.

cbse class 9 ganita manjari chapter 6 solutionscbse notesganita manjari class 9 exercise 6.3 solutionslet p be a point within itratio of the areas of the red regionsquare abcd