When the slope of distance-time graph is a straight line parallel to time axis, the object is stationary. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
When the slope of distance-time graph is a straight line parallel to time axis, the object is stationary.
• The slope of the distance-time graph for an object in uniform motion is straight line. • The slope of the distance-time graph for an object in non-uniform motion is not a straight line. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
• The slope of the distance-time graph for an object in uniform motion is straight line.
• The slope of the distance-time graph for an object in non-uniform motion is not a straight line.
Here we have, Initial velocity, u = 0 m/s Final velocity, v = 40 km/h = 40×1000/3600 ms⁻¹=100/9 ms⁻¹ Time (t) = 10 minute = 60 × 10 = 600 s Acceleration (a) =? We know that, v = u + at ⇒𝑎=𝑣−𝑢/𝑡=(100/9−0)600=1/54=0.0185 ms⁻² ⇒ a = 0.0185 ms⁻² For more answers visit to website: https://www.tiwariacadeRead more
Here we have,
Initial velocity, u = 0 m/s
Final velocity, v = 40 km/h = 40×1000/3600 ms⁻¹=100/9 ms⁻¹
Time (t) = 10 minute = 60 × 10 = 600 s
Acceleration (a) =?
We know that, v = u + at
⇒𝑎=𝑣−𝑢/𝑡=(100/9−0)600=1/54=0.0185 ms⁻²
⇒ a = 0.0185 ms⁻²
Here, 𝑢 = 80 𝑘𝑚/ℎ = 80×1000/3600 ms⁻¹=2009 ms⁻¹ 𝑣 = 60 𝑘𝑚/ℎ = 60×1000/3600 ms⁻¹=1509 ms⁻¹ 𝑡 = 5 𝑠 Therefore, acceleration, a =? We know that, v = u + at ⇒a=v-u/t= (150/9-200/9)/5=-50/46=-10/9=-1.1 ms⁻² Therefore, Acceleration is -1.1 ms⁻². For more answers visit to website: https://www.tiwariacademyRead more
Here, 𝑢 = 80 𝑘𝑚/ℎ = 80×1000/3600 ms⁻¹=2009 ms⁻¹
𝑣 = 60 𝑘𝑚/ℎ = 60×1000/3600 ms⁻¹=1509 ms⁻¹
𝑡 = 5 𝑠
Therefore, acceleration, a =?
We know that, v = u + at
⇒a=v-u/t= (150/9-200/9)/5=-50/46=-10/9=-1.1 ms⁻²
(i) A body is said in uniform acceleration when its motion is along a straight line and its velocity changes by equal magnitude in equal interval of time. (ii) A body is said in non-uniform acceleration when its motion is along a straight line and its velocity changes by unequal magnitude in equal iRead more
(i) A body is said in uniform acceleration when its motion is along a straight line and its velocity changes by equal magnitude in equal interval of time.
(ii) A body is said in non-uniform acceleration when its motion is along a straight line and its velocity changes by unequal magnitude in equal interval of time.
What can you say about the motion of an object whose distance-time graph is a straight line parallel to the time axis?
When the slope of distance-time graph is a straight line parallel to time axis, the object is stationary. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
When the slope of distance-time graph is a straight line parallel to time axis, the object is stationary.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
What is the nature of the distance-time graphs for uniform and non-uniform motion of an object?
• The slope of the distance-time graph for an object in uniform motion is straight line. • The slope of the distance-time graph for an object in non-uniform motion is not a straight line. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
• The slope of the distance-time graph for an object in uniform motion is straight line.
• The slope of the distance-time graph for an object in non-uniform motion is not a straight line.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h–1 in 10 minutes. Find its acceleration.
Here we have, Initial velocity, u = 0 m/s Final velocity, v = 40 km/h = 40×1000/3600 ms⁻¹=100/9 ms⁻¹ Time (t) = 10 minute = 60 × 10 = 600 s Acceleration (a) =? We know that, v = u + at ⇒𝑎=𝑣−𝑢/𝑡=(100/9−0)600=1/54=0.0185 ms⁻² ⇒ a = 0.0185 ms⁻² For more answers visit to website: https://www.tiwariacadeRead more
Here we have,
Initial velocity, u = 0 m/s
Final velocity, v = 40 km/h = 40×1000/3600 ms⁻¹=100/9 ms⁻¹
Time (t) = 10 minute = 60 × 10 = 600 s
Acceleration (a) =?
We know that, v = u + at
⇒𝑎=𝑣−𝑢/𝑡=(100/9−0)600=1/54=0.0185 ms⁻²
⇒ a = 0.0185 ms⁻²
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
A bus decreases its speed from 80 km h–1 to 60 km h–1 in 5 s. Find the acceleration of the bus.
Here, 𝑢 = 80 𝑘𝑚/ℎ = 80×1000/3600 ms⁻¹=2009 ms⁻¹ 𝑣 = 60 𝑘𝑚/ℎ = 60×1000/3600 ms⁻¹=1509 ms⁻¹ 𝑡 = 5 𝑠 Therefore, acceleration, a =? We know that, v = u + at ⇒a=v-u/t= (150/9-200/9)/5=-50/46=-10/9=-1.1 ms⁻² Therefore, Acceleration is -1.1 ms⁻². For more answers visit to website: https://www.tiwariacademyRead more
Here, 𝑢 = 80 𝑘𝑚/ℎ = 80×1000/3600 ms⁻¹=2009 ms⁻¹
𝑣 = 60 𝑘𝑚/ℎ = 60×1000/3600 ms⁻¹=1509 ms⁻¹
𝑡 = 5 𝑠
Therefore, acceleration, a =?
We know that, v = u + at
⇒a=v-u/t= (150/9-200/9)/5=-50/46=-10/9=-1.1 ms⁻²
Therefore, Acceleration is -1.1 ms⁻².
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
When will you say a body is in (i) uniform acceleration? (ii) non-uniform acceleration?
(i) A body is said in uniform acceleration when its motion is along a straight line and its velocity changes by equal magnitude in equal interval of time. (ii) A body is said in non-uniform acceleration when its motion is along a straight line and its velocity changes by unequal magnitude in equal iRead more
(i) A body is said in uniform acceleration when its motion is along a straight line and its velocity changes by equal magnitude in equal interval of time.
(ii) A body is said in non-uniform acceleration when its motion is along a straight line and its velocity changes by unequal magnitude in equal interval of time.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/