Here we have, Initial velocity, u = 0 m/s Acceleration (a) = 2 cm/s² = 0.02 m/s² Time (t) = 3 s Final velocity, v =? We know that, v = u + at Therefore, v = 0 + 0.02 × 3 m/s ⇒ v = 0.06 m/s Therefore the final velocity of trolley will be 0.06 m/s after start. For more answers visit to website: https:Read more
Here we have,
Initial velocity, u = 0 m/s
Acceleration (a) = 2 cm/s² = 0.02 m/s²
Time (t) = 3 s
Final velocity, v =?
We know that, v = u + at
Therefore, v = 0 + 0.02 × 3 m/s
⇒ v = 0.06 m/s
Therefore the final velocity of trolley will be 0.06 m/s after start.
Here, we have, Initial velocity, u = 90 km/h = 90×1000/3600 ms⁻¹=25 ms⁻¹ Final velocity, v = 0 m/s Acceleration, a = – 0.5 m/s² Distance travelled = ? Using, v2 = u2 + 2as s=v²−u²/2a=0²−25²/2(−0.5) = 625 m Therefore, train will go 625 m before it brought to rest. For more answers visit to website: hRead more
Here, we have,
Initial velocity, u = 90 km/h = 90×1000/3600 ms⁻¹=25 ms⁻¹
Final velocity, v = 0 m/s
Acceleration, a = – 0.5 m/s²
Distance travelled = ?
Using, v2 = u2 + 2as
s=v²−u²/2a=0²−25²/2(−0.5) = 625 m
Therefore, train will go 625 m before it brought to rest.
Here we have, Initial velocity (u) = 0 m/s Acceleration (a) = 0.1ms⁻² Time (t) = 2 minute = 120 seconds (a) The speed acquired: We know that, v = u + at ⇒ v = 0 + 0.1 × 120 m/s ⇒ v = 12 m/s Thus, the bus will acquire a speed of 12 m/s after 2 minute with the given acceleration. (b) The distance travRead more
Here we have,
Initial velocity (u) = 0 m/s
Acceleration (a) = 0.1ms⁻²
Time (t) = 2 minute = 120 seconds
(a) The speed acquired:
We know that, v = u + at
⇒ v = 0 + 0.1 × 120 m/s
⇒ v = 12 m/s
Thus, the bus will acquire a speed of 12 m/s after 2 minute with the given acceleration.
(b) The distance travelled
We know that, s = ut + 1/2at²
= 0 × 120 + 1/2 × 0.1 × (120) ²
= 1/2 × 0.1 ×14400 m = 720 m
Thus, bus will travel a distance of 720 m in the given time of 2 minute.
The quantity of distance is measured by the area occupied below the velocity time graph. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
The quantity of distance is measured by the area occupied below the velocity time graph.
When the graph of a speed time graph is a straight line parallel to the time axis, the object is moving with constant speed. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
When the graph of a speed time graph is a straight line parallel to the time axis, the object is moving with constant speed.
A trolley, while going down an inclined plane, has an acceleration of 2 cm s-2. What will be its velocity 3 s after the start?
Here we have, Initial velocity, u = 0 m/s Acceleration (a) = 2 cm/s² = 0.02 m/s² Time (t) = 3 s Final velocity, v =? We know that, v = u + at Therefore, v = 0 + 0.02 × 3 m/s ⇒ v = 0.06 m/s Therefore the final velocity of trolley will be 0.06 m/s after start. For more answers visit to website: https:Read more
Here we have,
Initial velocity, u = 0 m/s
Acceleration (a) = 2 cm/s² = 0.02 m/s²
Time (t) = 3 s
Final velocity, v =?
We know that, v = u + at
Therefore, v = 0 + 0.02 × 3 m/s
⇒ v = 0.06 m/s
Therefore the final velocity of trolley will be 0.06 m/s after start.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
A train is travelling at a speed of 90 km h–1. Brakes are applied so as to produce a uniform acceleration of – 0.5 m s-2. Find how far the train will go before it is brought to rest.
Here, we have, Initial velocity, u = 90 km/h = 90×1000/3600 ms⁻¹=25 ms⁻¹ Final velocity, v = 0 m/s Acceleration, a = – 0.5 m/s² Distance travelled = ? Using, v2 = u2 + 2as s=v²−u²/2a=0²−25²/2(−0.5) = 625 m Therefore, train will go 625 m before it brought to rest. For more answers visit to website: hRead more
Here, we have,
Initial velocity, u = 90 km/h = 90×1000/3600 ms⁻¹=25 ms⁻¹
Final velocity, v = 0 m/s
Acceleration, a = – 0.5 m/s²
Distance travelled = ?
Using, v2 = u2 + 2as
s=v²−u²/2a=0²−25²/2(−0.5) = 625 m
Therefore, train will go 625 m before it brought to rest.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
A bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes.
Here we have, Initial velocity (u) = 0 m/s Acceleration (a) = 0.1ms⁻² Time (t) = 2 minute = 120 seconds (a) The speed acquired: We know that, v = u + at ⇒ v = 0 + 0.1 × 120 m/s ⇒ v = 12 m/s Thus, the bus will acquire a speed of 12 m/s after 2 minute with the given acceleration. (b) The distance travRead more
Here we have,
Initial velocity (u) = 0 m/s
Acceleration (a) = 0.1ms⁻²
Time (t) = 2 minute = 120 seconds
(a) The speed acquired:
We know that, v = u + at
⇒ v = 0 + 0.1 × 120 m/s
⇒ v = 12 m/s
Thus, the bus will acquire a speed of 12 m/s after 2 minute with the given acceleration.
(b) The distance travelled
We know that, s = ut + 1/2at²
= 0 × 120 + 1/2 × 0.1 × (120) ²
= 1/2 × 0.1 ×14400 m = 720 m
Thus, bus will travel a distance of 720 m in the given time of 2 minute.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
What is the quantity which is measured by the area occupied below the velocity-time graph?
The quantity of distance is measured by the area occupied below the velocity time graph. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
The quantity of distance is measured by the area occupied below the velocity time graph.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
What can you say about the motion of an object if its speed time graph is a straight line parallel to the time axis?
When the graph of a speed time graph is a straight line parallel to the time axis, the object is moving with constant speed. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
When the graph of a speed time graph is a straight line parallel to the time axis, the object is moving with constant speed.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/