Given, side of the square field = 10 m Therefore, perimeter = 10 m × 4 = 40 m Farmer moves along the boundary in 40 s Time = 2 minutes 20 s = 2 × 60 s + 20 s = 140 s since, in 40 s farmer moves 40 m Therefore, in 1s distance covered by farmer = 40 ÷ 40 = 1m. Therefore, in 140s distance covered by faRead more
Given, side of the square field = 10 m
Therefore, perimeter = 10 m × 4 = 40 m
Farmer moves along the boundary in 40 s
Time = 2 minutes 20 s = 2 × 60 s + 20 s = 140 s
since, in 40 s farmer moves 40 m
Therefore, in 1s distance covered by farmer = 40 ÷ 40 = 1m.
Therefore, in 140s distance covered by farmer = 1 × 140 m = 140 m
Now, number of rotation to cover 140 along the boundary = 𝑇𝑜𝑡𝑎𝑙 𝑑𝑖𝑠𝑡𝑎𝑛𝑐𝑒/𝑃𝑒𝑟𝑖𝑚𝑒𝑡𝑒𝑟
= 140 m ÷ 40 m = 3.5 round
Thus after 3.5 round farmer will at point C (diagonally opposite to his initial position) of the field.
Therefore, Displacement AC= √(〖10〗^2+〖10〗^2 ) =√200 = √(10&2) m
Thus, after 2 minute 20 second the displacement of farmer will be equal to√(10&2 )m north east from initial position.
Yes, zero displacement is possible if an object has moved through a distance. Suppose a body is moving in a circular path and starts moving from point A and it returns back at same point A after completing one revolution, then the distance will be equal to its circumference while displacement will bRead more
Yes, zero displacement is possible if an object has moved through a distance.
Suppose a body is moving in a circular path and starts moving from point A and it returns back at same point A after completing one revolution, then the distance will be equal to its circumference while displacement will be zero.
Which of the following is true for displacement?
None of (a) and (b) are true. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
None of (a) and (b) are true.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?
Given, side of the square field = 10 m Therefore, perimeter = 10 m × 4 = 40 m Farmer moves along the boundary in 40 s Time = 2 minutes 20 s = 2 × 60 s + 20 s = 140 s since, in 40 s farmer moves 40 m Therefore, in 1s distance covered by farmer = 40 ÷ 40 = 1m. Therefore, in 140s distance covered by faRead more
Given, side of the square field = 10 m
Therefore, perimeter = 10 m × 4 = 40 m
Farmer moves along the boundary in 40 s
Time = 2 minutes 20 s = 2 × 60 s + 20 s = 140 s
since, in 40 s farmer moves 40 m
Therefore, in 1s distance covered by farmer = 40 ÷ 40 = 1m.
Therefore, in 140s distance covered by farmer = 1 × 140 m = 140 m
Now, number of rotation to cover 140 along the boundary = 𝑇𝑜𝑡𝑎𝑙 𝑑𝑖𝑠𝑡𝑎𝑛𝑐𝑒/𝑃𝑒𝑟𝑖𝑚𝑒𝑡𝑒𝑟
= 140 m ÷ 40 m = 3.5 round
Thus after 3.5 round farmer will at point C (diagonally opposite to his initial position) of the field.
Therefore, Displacement AC= √(〖10〗^2+〖10〗^2 ) =√200 = √(10&2) m
Thus, after 2 minute 20 second the displacement of farmer will be equal to√(10&2 )m north east from initial position.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
An object has moved through a distance. Can it have zero displacement? If yes, support your answer with an example.
Yes, zero displacement is possible if an object has moved through a distance. Suppose a body is moving in a circular path and starts moving from point A and it returns back at same point A after completing one revolution, then the distance will be equal to its circumference while displacement will bRead more
Yes, zero displacement is possible if an object has moved through a distance.
Suppose a body is moving in a circular path and starts moving from point A and it returns back at same point A after completing one revolution, then the distance will be equal to its circumference while displacement will be zero.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/