Inertia is the measure of the mass of the body. The greater is the mass of the body; the greater is its inertia and vice-versa. (a) Mass of a stone is more than the mass of a rubber ball for the same size. Hence, inertia of the stone is greater than that of a rubber ball. (b) Mass of a train is moreRead more
Inertia is the measure of the mass of the body. The greater is the mass of the body; the greater is its inertia and vice-versa.
(a) Mass of a stone is more than the mass of a rubber ball for the same size. Hence, inertia of the stone is greater than that of a rubber ball.
(b) Mass of a train is more than the mass of a bicycle. Hence, inertia of the train is greater than that of the bicycle.
(c) Mass of a five rupee coin is more than that of a one-rupee coin. Hence, inertia of the five rupee coin is greater than that of the one-rupee coin.
Here, r = 42250 km = 42250000 m T = 24 h = 24 × 60 × 60 s Using Speed, v = 2πr ÷ T v = (2 × 3.14 × 42250000) ÷ (24 × 60 × 60) m/s = 3070.9 m/s = 3.07 km/s For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
Here,
r = 42250 km = 42250000 m
T = 24 h = 24 × 60 × 60 s
Using Speed, v = 2πr ÷ T
v = (2 × 3.14 × 42250000) ÷ (24 × 60 × 60) m/s
= 3070.9 m/s = 3.07 km/s
(a) Yes, a body can have acceleration even when its velocity is zero. When a body is thrown up, at highest point its velocity is zero but it has acceleration equal to acceleration due to gravity. (b) Yes, an acceleration moving horizontally is acted upon by acceleration due to gravity that acts vertRead more
(a) Yes, a body can have acceleration even when its velocity is zero. When a body is thrown up, at highest point its velocity is zero but it has acceleration equal to acceleration due to gravity.
(b) Yes, an acceleration moving horizontally is acted upon by acceleration due to gravity that acts vertically downwards.
Here, u = 0 m/s, s = 20 m, a = 10 ms⁻², v = ?, t = ? Using v² – u² = 2as We have, v² – 0² = 2 × 10 × 20 = 400 ⇒ v = 20 ms⁻¹. and t = (v – u) ÷ a = 20 ÷ 10 = 2 s. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
Here, u = 0 m/s, s = 20 m, a = 10 ms⁻², v = ?, t = ?
Using v² – u² = 2as
We have, v² – 0² = 2 × 10 × 20 = 400 ⇒ v = 20 ms⁻¹.
and t = (v – u) ÷ a = 20 ÷ 10 = 2 s.
Here, u = 0 m/s a = 3 ms⁻² t = 8 s Using, s = ut + ½ at² s = 0 × 8 + ½ × 3 × 8² = 96 m. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
Here, u = 0 m/s
a = 3 ms⁻²
t = 8 s
Using, s = ut + ½ at²
s = 0 × 8 + ½ × 3 × 8² = 96 m.
Which of the following has more inertia?
Inertia is the measure of the mass of the body. The greater is the mass of the body; the greater is its inertia and vice-versa. (a) Mass of a stone is more than the mass of a rubber ball for the same size. Hence, inertia of the stone is greater than that of a rubber ball. (b) Mass of a train is moreRead more
Inertia is the measure of the mass of the body. The greater is the mass of the body; the greater is its inertia and vice-versa.
(a) Mass of a stone is more than the mass of a rubber ball for the same size. Hence, inertia of the stone is greater than that of a rubber ball.
(b) Mass of a train is more than the mass of a bicycle. Hence, inertia of the train is greater than that of the bicycle.
(c) Mass of a five rupee coin is more than that of a one-rupee coin. Hence, inertia of the five rupee coin is greater than that of the one-rupee coin.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth.
Here, r = 42250 km = 42250000 m T = 24 h = 24 × 60 × 60 s Using Speed, v = 2πr ÷ T v = (2 × 3.14 × 42250000) ÷ (24 × 60 × 60) m/s = 3070.9 m/s = 3.07 km/s For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
Here,
r = 42250 km = 42250000 m
T = 24 h = 24 × 60 × 60 s
Using Speed, v = 2πr ÷ T
v = (2 × 3.14 × 42250000) ÷ (24 × 60 × 60) m/s
= 3070.9 m/s = 3.07 km/s
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
State which of the following situations are possible and give an example for each of these:
(a) Yes, a body can have acceleration even when its velocity is zero. When a body is thrown up, at highest point its velocity is zero but it has acceleration equal to acceleration due to gravity. (b) Yes, an acceleration moving horizontally is acted upon by acceleration due to gravity that acts vertRead more
(a) Yes, a body can have acceleration even when its velocity is zero. When a body is thrown up, at highest point its velocity is zero but it has acceleration equal to acceleration due to gravity.
(b) Yes, an acceleration moving horizontally is acted upon by acceleration due to gravity that acts vertically downwards.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10 m s-2, with what velocity will it strike the ground? After what time will it strike the ground?
Here, u = 0 m/s, s = 20 m, a = 10 ms⁻², v = ?, t = ? Using v² – u² = 2as We have, v² – 0² = 2 × 10 × 20 = 400 ⇒ v = 20 ms⁻¹. and t = (v – u) ÷ a = 20 ÷ 10 = 2 s. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
Here, u = 0 m/s, s = 20 m, a = 10 ms⁻², v = ?, t = ?
Using v² – u² = 2as
We have, v² – 0² = 2 × 10 × 20 = 400 ⇒ v = 20 ms⁻¹.
and t = (v – u) ÷ a = 20 ÷ 10 = 2 s.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
A motorboat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 m s–2 for 8.0 s. How far does the boat travel during this time?
Here, u = 0 m/s a = 3 ms⁻² t = 8 s Using, s = ut + ½ at² s = 0 × 8 + ½ × 3 × 8² = 96 m. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/
Here, u = 0 m/s
a = 3 ms⁻²
t = 8 s
Using, s = ut + ½ at²
s = 0 × 8 + ½ × 3 × 8² = 96 m.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-8/