We substitute a = 3/4 s and b = 8t into the square identity. Squaring the terms independently and simplifying the middle multiplication step gives the final plain algebraic text solution.
Using the identity (a + b) square = a square + 2ab + b square, expand (3/4 s + 8t) square
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To expand this binomial, we apply the standard square formula where a represents 3/4 s and b represents 8t. Squaring the first term results in 9/16 s square, and squaring the second term yields 64t square. The middle cross-product term is calculated by multiplying two times 3/4 s times 8t, which simplifies directly to the integer 12st. Putting all parts together gives the answer.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/