K.E. of a body is increased by 300 %. Find the % increase in its momentum?

K.E = P²/2m sp p = √2mk
Increase in K.E. = 300% of k = 3k
Final K.E., k ′ = k + 3k = 4k
Final momentum, p′= √2mk = √(2m X 4k) = √(2&2mk)
= 2p
% Increase in momentum = p’ – p/p X 100 = 100%