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Vakti Singh
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Asked: 2021-02-12T08:30:12+00:00 In:

K.E. of a body is increased by 300 %. Find the % increase in its momentum?

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NCERT Solutions for Class 11 Science Work energy and power 4
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Work energy and power
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2020-2021cbsechapter 4class 11class 11 sciencencertphysicssciencework energy and power
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    1 Answer

    1. K.E = P²/2m sp p = √2mk
      Increase in K.E. = 300% of k = 3k
      Final K.E., k ′ = k + 3k = 4k
      Final momentum, p′= √2mk = √(2m X 4k) = √(2&2mk)
      = 2p
      % Increase in momentum = p’ – p/p X 100 = 100%

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