If a body is heated from 27° C to 92.7 °C, then the ratio of their energies of radiations emitted will be
Energies of radiations refer to the energy carried by electromagnetic waves across different wavelengths. These include visible light, ultraviolet, infrared, X-rays, and gamma rays. The energy of radiation is directly proportional to its frequency and inversely proportional to its wavelength, as described by the equation E = hf, where h is Planck’s constant.
Class 11 Physics Chapter 10 Thermal Properties of Matter covers key concepts like heat transfer specific heat capacity thermal expansion and calorimetry. It explains conduction convection and radiation and introduces the concept of thermal equilibrium. The chapter also discusses the laws of heat transfer and their applications which are vital for the CBSE Exam 2024-25.
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The energy radiated by a body is given by the Stefan-Boltzmann law:
E ∝ T⁴
where E is the energy emitted and T is the temperature in Kelvin.
To find the ratio of the energies emitted at two temperatures, we use the formula:
(E₂ / E₁) = (T₂ / T₁)⁴
First, convert the temperatures from Celsius to Kelvin:
T₁ = 27 + 273 = 300 K T₂ = 92.7 + 273 = 365.7 K
Now, find the ratio:
(E₂ / E₁) = (365.7 / 300)⁴ ≈ (1.219)⁴ ≈ 2.1⁴ ≈ 16
So, the ratio of the energies emitted is 1 : 16.
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