This polynomial fits the standard identity a square + 2ab + b square. We rewrite 4s square as (2s) square and 25t square as (5t) square, giving the factored result of (2s + 5t) square.
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We look at the structure of the polynomial to find its factors. The first term 4s square is the square of 2s, and the final term 25t square is the square of 5t. The middle term 20st is exactly equal to two multiplied by 2s multiplied by 5t. This allows us to use the regular addition square identity, giving us a clean and complete factorization of (2s + 5t) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/