NCERT Solutions for Class 9 Maths Chapter 2

Important NCERT Questions

Polynomials

NCERT Books for Session 2022-2023

CBSE Board and UP Board Others state Board

EXERCISE 2.4

Page No:44

Questions No:3 part:3

# Find the value of k, if x – 1 is a factor of p(x) in the following cases: p(x) = kx² – √2 x + 1

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(iii) p(x) = kx² – √2 x + 1

Putting x – 1 = 0, we get, x = 1

Using remainder theorem, when p(x) = kx² – √2 x + 1 is divided by x – 1, remainder is given by p(1)

= k(1)² – √2(1) + 1

= k – √2 + 1

Since x – 1 is a factor of p(x), hence remainder p(1) = 0

⇒ k – √2 + 1 = 0

⇒ k = √2 – 1