NCERT Solutions for Class 10 Maths Chapter 5

Important NCERT Questions

Arithmetic Progression

NCERT Books for Session 2022-2023

CBSE Board and UP Board Others state Board

EXERCISE 5.3

Page No:107

Questions No:2

# Find the sums given below :34 + 32 + 30 + . . . + 10

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Here, a = 34 and d = 32 – 34 = – 2.

Let, the nth term of the A.P. is 10.

Therefore, a_n = 10

⇒ a + (n -1)d = 10

⇒ 34 + (n – 1)(-2) = 10

⇒ (n -1)(- 2) = – 24

⇒ n -1 = 12

⇒ n = 13

The sum of n terms of an AP is given by

S_n = n/2[a + l]

⇒ S₁₃ = 13/2[34 + 10]

⇒ S₁₃ = 13/2[44]

= 13 × 22 = 286

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