This six-term polynomial matches the three-term square identity. Looking at the negative signs, the bases for both v and w must be negative to yield the correct cross-product signs.
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This six-term polynomial matches the three-term square identity. Looking at the negative signs, the bases for both v and w must be negative to yield the correct cross-product signs.
To factor this long polynomial, we examine the perfect square bases which are 8u, 11v and 2w. We observe that the cross-product terms 176uv and 32uw are negative, while 44vw is positive. Because the product of v and w becomes positive while their separate combinations with u are negative, both the 11v and 2w bases must carry negative signs. This produces the complete factored solution (8u – 11v – 2w) square.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/