This six-term polynomial matches the three-term square identity. Looking at the negative signs, the bases for both v and w must be negative to yield the correct cross-product signs.
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We split the middle coefficient minus 1 into minus 7 and positive 6 because their sum equals minus 1 and their product equals minus 42, giving the linear binomial factors.
We express the product as (20 – 2) (30 – 1) and expand using the distributive property. Evaluating the separate numerical products step by step gives the clean final total.
Virat
Asked: In: Class 9 Maths
We express 27 as 30 – 3 and utilize the subtraction square identity. Squaring the terms and subtracting their double cross-product leaves the final calculation of 729.
Virat
Asked: In: Class 9 Maths
We split the middle term 7x into 3x plus 4x. Factoring the expressions in pairs gives the two linear binomial factors which are (2x + 1) and (3x + 2).