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Ayaan Khan
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Asked: 2020-12-26T04:22:21+00:00 In:

D and E are points on the sides CA and CB respectively of a triangle ABC right angled at C. Prove that AE² + BD² = AB²+ DE².

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NCERT Solutions for Class 10 Maths Chapter 6
Important NCERT Questions
Triangles
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 6.5
Page No:151
Questions No:13

2020-2021cbsechapter 6class10mathematicsncerttriangles
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    1. D and E are points on the sides CA and CB respectively of a triangle ABC right angled at C. Prove that AE² + BD² = AB²+ DE².

      In ΔACE, by pythagoes thoeorem
      AC² + CE² AE² …(1)
      In ΔBCD, by Pythagoras theorem
      BC² + CD² = DB² …(2)
      From the equation (1) and (2), we have
      AC² + CE² + BC² + CD² = AE² + DB ² …(3)
      In ΔBCD, by pythagoras theorem
      DE² = CD² + CE² …(4)
      In ΔABC, by pythagoras theorem
      AB² = AC² + CB² …(5)
      From the equation (3), (4) and (5), we have
      DE² + AB² = AE² + DB²

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    3. Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
      Please follow the link to visit website for first and second term exams solutions.
      https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-6/

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