Calculate the force required to move a train of 2000 quintal up on an incline plane of 1 in 50 with an acceleration of 2 ms⁻². The force of friction per quintal is 0.5 N.

Force of friction = 0·5 N per quintal
f = 0·5 × 2000 = 1000 N
m = 2000 quintals = 2000 × 100 kg
sin θ = 1/50, a= 2m/s²
In moving up an inclined plane, force required against gravity
= mg sin θ = 39200 N
And force required to produce acceleration = ma
= 2000 × 100 × 2 = 40,0000 N
Total force required = 1000 + 39,200 + 40,0000
= 440200 N.