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Calculate the force required to move a train of 2000 quintal up on an incline plane of 1 in 50 with an acceleration of 2 ms⁻². The force of friction per quintal is 0.5 N.

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NCERT Solutions for Class 11 Science Newton’s law of motion and friction 3
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Newton’s law of motion and friction
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1 Answer

  1. Force of friction = 0·5 N per quintal
    f = 0·5 × 2000 = 1000 N
    m = 2000 quintals = 2000 × 100 kg
    sin θ = 1/50, a= 2m/s²
    In moving up an inclined plane, force required against gravity
    = mg sin θ = 39200 N
    And force required to produce acceleration = ma
    = 2000 × 100 × 2 = 40,0000 N
    Total force required = 1000 + 39,200 + 40,0000
    = 440200 N.

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