This six-term polynomial matches the three-term square identity. Looking at the negative signs, the bases for both v and w must be negative to yield the correct cross-product signs.
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The polynomial matches the identity template a square – 2ab + b square. Since 16s square is (4s) square and 25t square is (5t) square, it condenses directly into (4s – 5t) square.
We rewrite the terms as (40 – 6) (40 + 3) and utilize the standard quadratic expansion identity. Computing the numerical components yields the final plain text answer.
We rewrite 97 as 100 – 3 and apply the subtraction square identity. Squaring 100 and 3, then subtracting twice their product gives the plain numerical solution.
We express 27 as 30 – 3 and utilize the subtraction square identity. Squaring the terms and subtracting their double cross-product leaves the final calculation of 729.