With initial salary of 5,00,000 and annual increment of 20,000, his earnings form an AP. Solving 7,00,000 = 5,00,000 + (n – 1) x 20,000 gives n = 11, meaning his income reaches 7,00,000 after 10 years.
Harish started work at an annual salary of ₹5,00,000 and received an increment of ₹20,000 each year. After how many years did his income reach ₹7,00,000?
Share
Harish’s yearly income forms an arithmetic progression where:
First term a = 500000
Common difference d = 20000
Target term tn = 700000.
Using the nth term formula tn = a + (n – 1)d:
700000 = 500000 + (n – 1) x 20000
200000 = (n – 1) x 20000
n – 1 = 10
n = 11.
Since n = 11 represents the 11th year of his career, it required 10 annual increments.
Therefore, his income reached 7,00,000 after 10 years.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 8 Predicting What Comes Next: Exploring Sequences and Progressions Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-8/