The breaking tension of a wire is proportional to its cross-sectional area. It can be determined using the formula: A = (π × d²) / 4 Step 1: Determine the areas First wire (diameter = 1 mm): A₁ = (π × 1²) / 4 = π / 4 Second wire (diameter = 2 mm): A₂ = (π × 2²) / 4 = 4π / 4 = π The area of the seconRead more
The breaking tension of a wire is proportional to its cross-sectional area. It can be determined using the formula:
A = (π × d²) / 4
Step 1: Determine the areas
First wire (diameter = 1 mm):
A₁ = (π × 1²) / 4 = π / 4
Second wire (diameter = 2 mm):
A₂ = (π × 2²) / 4 = 4π / 4 = π
The area of the second wire is **4 times** the area of the first wire.
Step 2: Calculate the breaking tension
Breaking tension is proportional to the area.
For the first wire:
T₁ = 1000 N
For the second wire:
T₂ = 4 × T₁ = 4 × 1000 = 4000 N
A wire of diameter 1 mm breaks under a tension 0f 1000 N. Another wire, of same material as that of the first one, but of diameter 2mm breaks under a tension of
The breaking tension of a wire is proportional to its cross-sectional area. It can be determined using the formula: A = (π × d²) / 4 Step 1: Determine the areas First wire (diameter = 1 mm): A₁ = (π × 1²) / 4 = π / 4 Second wire (diameter = 2 mm): A₂ = (π × 2²) / 4 = 4π / 4 = π The area of the seconRead more
The breaking tension of a wire is proportional to its cross-sectional area. It can be determined using the formula:
A = (π × d²) / 4
Step 1: Determine the areas
First wire (diameter = 1 mm):
A₁ = (π × 1²) / 4 = π / 4
Second wire (diameter = 2 mm):
A₂ = (π × 2²) / 4 = 4π / 4 = π
The area of the second wire is **4 times** the area of the first wire.
Step 2: Calculate the breaking tension
Breaking tension is proportional to the area.
For the first wire:
T₁ = 1000 N
For the second wire:
T₂ = 4 × T₁ = 4 × 1000 = 4000 N
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/