Most metals have a Poisson's ratio in the range of 0 to 0.5. A value of 0 indicates no lateral contraction when stretched, and 0.5 represents a material that maintains constant volume under deformation. This is theoretically true for perfectly incompressible materials.
Most metals have a Poisson’s ratio in the range of 0 to 0.5. A value of 0 indicates no lateral contraction when stretched, and 0.5 represents a material that maintains constant volume under deformation. This is theoretically true for perfectly incompressible materials.
Work done per unit volume in deforming a body is given by the formula: Work done per unit volume = 1/2 × Stress × Strain This is derived from the area under stress-strain curve for elastic deformation, which forms a triangle. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-1Read more
Work done per unit volume in deforming a body is given by the formula:
Work done per unit volume = 1/2 × Stress × Strain
This is derived from the area under stress-strain curve for elastic deformation, which forms a triangle.
Formula: The potential energy per unit volume of a taut wire may be given as follows: Energy per unit volume = ½ × Stress × Strain For a wire: Tension = Stress Stress = Y × Strain Substituting Stress to above equation: Potential Energy per unit volume = 1/2 x (Yx X) × X= 0.5Yx² Click for more: hRead more
Formula:
The potential energy per unit volume of a taut wire may be given as follows:
Energy per unit volume = ½ × Stress × Strain
For a wire:
Tension = Stress
Stress = Y × Strain
Substituting Stress to above equation:
Potential Energy per unit volume = 1/2 x (Yx X) × X= 0.5Yx²
The extension due to the weight of the rope can be found using the following formula: ΔL = (F L) / (A Y) Where: - F = Force due to weight = mg - L = Length of the rope = 8 m - A = Cross-sectional area of the rope - Y = Young's modulus - m = mass of the rope = density × volume - Volume = A × L AfterRead more
The extension due to the weight of the rope can be found using the following formula:
ΔL = (F L) / (A Y)
Where:
– F = Force due to weight = mg
– L = Length of the rope = 8 m
– A = Cross-sectional area of the rope
– Y = Young’s modulus
– m = mass of the rope = density × volume
– Volume = A × L
After computation, we get that the stretch is approximately:
The work done (W) in elongating a rod is given by the formula: W = 1/2 × Stress × Strain × Volume Where: - Stress = Force / Area - Strain = ΔL / L (elongation per unit length) As elongation, ΔL, is proportional to the applied force and Young's modulus, work done is proportional to the square of theRead more
The work done (W) in elongating a rod is given by the formula:
W = 1/2 × Stress × Strain × Volume
Where:
– Stress = Force / Area
– Strain = ΔL / L (elongation per unit length)
As elongation, ΔL, is proportional to the applied force and Young’s modulus, work done is proportional to the square of the elongation.
Minimum and maximum values of possion’s ratio for a metal lies between
Most metals have a Poisson's ratio in the range of 0 to 0.5. A value of 0 indicates no lateral contraction when stretched, and 0.5 represents a material that maintains constant volume under deformation. This is theoretically true for perfectly incompressible materials.
Most metals have a Poisson’s ratio in the range of 0 to 0.5. A value of 0 indicates no lateral contraction when stretched, and 0.5 represents a material that maintains constant volume under deformation. This is theoretically true for perfectly incompressible materials.
See lessThe work done per unit volume in deforming a body is given by
Work done per unit volume in deforming a body is given by the formula: Work done per unit volume = 1/2 × Stress × Strain This is derived from the area under stress-strain curve for elastic deformation, which forms a triangle. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-1Read more
Work done per unit volume in deforming a body is given by the formula:
Work done per unit volume = 1/2 × Stress × Strain
This is derived from the area under stress-strain curve for elastic deformation, which forms a triangle.
Click here for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/
If in a wire of Young’s modulus Y, longitudinal strain X is produced, then the value of potential energy stored in its unit volume will be
Formula: The potential energy per unit volume of a taut wire may be given as follows: Energy per unit volume = ½ × Stress × Strain For a wire: Tension = Stress Stress = Y × Strain Substituting Stress to above equation: Potential Energy per unit volume = 1/2 x (Yx X) × X= 0.5Yx² Click for more: hRead more
Formula:
The potential energy per unit volume of a taut wire may be given as follows:
Energy per unit volume = ½ × Stress × Strain
For a wire:
Tension = Stress
Stress = Y × Strain
Substituting Stress to above equation:
Potential Energy per unit volume = 1/2 x (Yx X) × X= 0.5Yx²
Click for more:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/
A thick copper rope of density 1.5 x 10³ kgm⁻³ and Young’s modulus 5 x 10⁶ Nm⁻², 8 m in length, its length due to its own weight is
The extension due to the weight of the rope can be found using the following formula: ΔL = (F L) / (A Y) Where: - F = Force due to weight = mg - L = Length of the rope = 8 m - A = Cross-sectional area of the rope - Y = Young's modulus - m = mass of the rope = density × volume - Volume = A × L AfterRead more
The extension due to the weight of the rope can be found using the following formula:
ΔL = (F L) / (A Y)
Where:
– F = Force due to weight = mg
– L = Length of the rope = 8 m
– A = Cross-sectional area of the rope
– Y = Young’s modulus
– m = mass of the rope = density × volume
– Volume = A × L
After computation, we get that the stretch is approximately:
ΔL = 9.6 x 10⁻⁵ m
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/
A metallic rod of length l and cross – sectional area A is made of a material of Young’s modulus Y. If the rod is elongated by an amount y, then the work done is proportional to
The work done (W) in elongating a rod is given by the formula: W = 1/2 × Stress × Strain × Volume Where: - Stress = Force / Area - Strain = ΔL / L (elongation per unit length) As elongation, ΔL, is proportional to the applied force and Young's modulus, work done is proportional to the square of theRead more
The work done (W) in elongating a rod is given by the formula:
W = 1/2 × Stress × Strain × Volume
Where:
– Stress = Force / Area
– Strain = ΔL / L (elongation per unit length)
As elongation, ΔL, is proportional to the applied force and Young’s modulus, work done is proportional to the square of the elongation.
Therefore, work done is proportional to y².
Check for more info:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/