This matches the three-term identity where the term containing variable b must be negative because both cross-product terms that include b have a minus sign in the expression.
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Virat
Asked: In: Class 9 Maths
We express 27 as 30 – 3 and utilize the subtraction square identity. Squaring the terms and subtracting their double cross-product leaves the final calculation of 729.
Virat
Asked: In: Class 9 Maths
We change 41 into 40 + 1 and apply the addition square identity. Squaring 40 and 1, then adding twice their product gives the plain numerical solution.
Virat
Asked: In: Class 9 Maths
We split the middle term 7x into 3x plus 4x. Factoring the expressions in pairs gives the two linear binomial factors which are (2x + 1) and (3x + 2).
Virat
Asked: In: Class 9 Maths
We split the middle term minus 11x into minus 15x plus 4x. Factoring by grouping yields the two expressions, filling the blanks with the number 3 and the term 5x.