Class 9 Science Exploration Notes for First Term Exam (2026-27). These notes provide chapter-wise concepts, important definitions, formulas, diagrams and exam-focused questions to help students revise effectively and prepare confidently for their first-term examination.
Discussion Forum Latest Questions
Virat
Asked: In: Class 9 Science
The student travels 4 × 3 = 12 m upward and then 2 × 3 = 6 m downward. Therefore, total distance = 18 m and displacement from the ground floor = 6 m upward.
Virat
Asked: In: Class 9 Science
He travelled 250 m four times: home to shop, shop to home, home to shop and shop to home. Therefore, total distance = 1000 m. Since he returned home, displacement = 0 m.
a shop from home which is located at a distance of 250 mbought provisions and came back homeclass 9 science chapter 4 describing motion around us solutionsexploration class 9 chapter 4 describing motion around us solutionsncert solutions for class 9 science exploration chapter 4what was his displacement from home
Virat
Asked: In: Class 9 Science
The displacement of the athlete will be zero when she returns to the starting point O. In that case, she travels 100 m from O to A and 100 m back to O. Total distance = 200 m.
Yes, the safe distance depends on the speed of the vehicle. As speed increases, the stopping distance increases. Therefore, a vehicle moving faster must maintain a greater distance from the vehicle ahead.