The minute hand completes 1.5 revolutions in 90 minutes. Distance = 1.5 × 2π × 7 = 21π cm. Displacement = 14 cm. Average speed = 21π/5400 cm s⁻¹ and average velocity = 14/5400 cm s⁻¹ downward.
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The distance travelled is approximately equal to the area under the velocity-time graph. Estimating the areas of the trapeziums from the graph gives a total distance of approximately 45 km.
The correct options are (i) and (ii). Both objects have the same initial and final positions, so their average velocities are equal. They also cover the same total distance in 10 seconds, making their average speeds equal.
Given, initial velocity u = 0, final velocity v = 24 m s⁻¹ and time t = 6 s. Average acceleration = (24 − 0)/6 = 4 m s⁻². Distance = ½(0 + 24) × 6 = 72 m.
Yes, the ball undergoes straight-line motion along the inclined track. Its motion can be represented by a horizontal line. Since the ball moves in one direction without reversing, total distance and displacement magnitude are equal at A, B, C and ...