1. Let ABCD be a cyclic quadrilateral and let CD be extended to E. Then ∠CDE and ∠CDA form a linear pair, so their sum is 180°. Also, opposite angles of a cyclic quadrilateral are supplementary. Therefore, ∠ABC + ∠CDA = 180° and ∠CDE + ∠CDA = 180°. Hence, ∠CDE = ∠ABC. Thus, the exterior angle of a cyclRead more

    Let ABCD be a cyclic quadrilateral and let CD be extended to E. Then ∠CDE and ∠CDA form a linear pair, so their sum is 180°. Also, opposite angles of a cyclic quadrilateral are supplementary.

    Therefore,

    ∠ABC + ∠CDA = 180°

    and

    ∠CDE + ∠CDA = 180°.

    Hence,

    ∠CDE = ∠ABC.

    Thus, the exterior angle of a cyclic quadrilateral is equal to its interior opposite angle.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

    See less
    • 18
  2. OA and OB are radii of the circle, so OA = OB = 12 cm. Therefore, triangle AOB is isosceles. Since ∠AOB = 60°, the remaining two angles together are 120° and each is 60°. Hence, triangle AOB is an equilateral triangle. All its sides are equal. Therefore, AB = OA = OB = 12 cm. So, the length of chordRead more

    OA and OB are radii of the circle, so OA = OB = 12 cm. Therefore, triangle AOB is isosceles. Since ∠AOB = 60°, the remaining two angles together are 120° and each is 60°. Hence, triangle AOB is an equilateral triangle. All its sides are equal. Therefore, AB = OA = OB = 12 cm. So, the length of chord AB is 12 cm.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

    See less
    • 112
  3. No. There cannot be such points X and Y on the same side of AB for which ∠AXB is different from ∠AYB. According to Theorem 9, an arc subtends the same angle at every point on the remaining part of the circle. Therefore, when X and Y lie on the same side of AB, both angles subtend the same chord AB aRead more

    No. There cannot be such points X and Y on the same side of AB for which ∠AXB is different from ∠AYB. According to Theorem 9, an arc subtends the same angle at every point on the remaining part of the circle. Therefore, when X and Y lie on the same side of AB, both angles subtend the same chord AB and are equal.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

    See less
    • 117
  4. Yes. If ∠AXB = ∠AYB and X and Y lie on the same side of AB, then both points lie on the same segment of the circle. The angle subtended by a chord at points on the same segment is equal. Hence, equal angles are obtained at X and Y. This follows directly from the property that an arc subtends equal aRead more

    Yes. If ∠AXB = ∠AYB and X and Y lie on the same side of AB, then both points lie on the same segment of the circle. The angle subtended by a chord at points on the same segment is equal. Hence, equal angles are obtained at X and Y. This follows directly from the property that an arc subtends equal angles at points on the remaining part of the circle.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

    See less
    • 114
  5. Yes. Since ∠AXB = ∠AYB, the line segment AB subtends equal angles at X and Y. If X and Y are on the same side of AB, Theorem 10 states that the four points A, B, X and Y lie on a circle. Therefore, the circle passing through A, B and X will also pass through Y. Thus, A, B, X and Y are concyclic.Read more

    Yes. Since ∠AXB = ∠AYB, the line segment AB subtends equal angles at X and Y. If X and Y are on the same side of AB, Theorem 10 states that the four points A, B, X and Y lie on a circle. Therefore, the circle passing through A, B and X will also pass through Y. Thus, A, B, X and Y are concyclic.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

    See less
    • 113