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Rishipal

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  1. Asked: November 29, 2021In: Class 9 Science

    Velocity time graph for a moving object is found to be curved line, then its acceleration is:

    Rishipal
    Added an answer on November 30, 2021 at 3:03 am

    [B] variable

    [B] variable

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  2. Asked: November 29, 2021In: Class 9 Science

    A truck moving with a speed of 54 km/h. Truck driver applied brakes suddenly and brings the truck to rest in 5 s, then the average retarding force on truck, if mass of the truck and driver is 400 kg, will be:

    Rishipal
    Added an answer on November 30, 2021 at 3:03 am

    (A) 1200 N

    (A) 1200 N

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  3. Asked: November 29, 2021In: Class 9 Science

    Intestine absorb the digested food materials. What type of epithelial cells are responsible for that?

    Rishipal
    Added an answer on November 30, 2021 at 3:03 am

    (B) Columnar epithelium

    (B) Columnar epithelium

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  4. Asked: November 29, 2021In: Class 9 Science

    A Train starting from rest attains a velocity of 90 km/h in 2 min, then the distance travelled by the train for attaining this velocity is:

    Best Answer
    Rishipal
    Added an answer on November 30, 2021 at 3:03 am

    (A) 1.5 km Given, u = 0, v = 90 km/h = 90 x 5/18 = 25 m/s From the equation of motion, v = u + at a = v/t or, 25/2x60 or, 5/24 m/s² Distance covered is: S = ut + 1/2 at² = 0 + 1/2 x 5/24 x (120)² = 1/2 x 5/24 x 120 x 120 = 1500 m = 1.5 km

    (A) 1.5 km
    Given, u = 0, v = 90 km/h = 90 x 5/18 = 25 m/s
    From the equation of motion,
    v = u + at
    a = v/t
    or, 25/2×60
    or, 5/24 m/s²
    Distance covered is:
    S = ut + 1/2 at²
    = 0 + 1/2 x 5/24 x (120)²
    = 1/2 x 5/24 x 120 x 120
    = 1500 m
    = 1.5 km

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  5. Asked: November 29, 2021In: Class 9 Science

    A car retards uniformly at the rate of 5 m/s² and stops in 10 s. The initial velocity of car is:

    Rishipal
    Added an answer on November 30, 2021 at 3:03 am

    (C) 50 m/s Given, velocity, v = 0, acceleration, a = - 5m/s² from equation of motion, v = u + at Or, u = - at = - (-5) × 10 = 50 m/s

    (C) 50 m/s
    Given, velocity, v = 0, acceleration, a = – 5m/s² from equation of motion, v = u + at
    Or, u = – at = – (-5) × 10 = 50 m/s

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