A truck moving with a speed of 54 km/h. Truck driver applied brakes suddenly and brings the truck to rest in 5 s, then the average retarding force on truck, if mass of the truck and driver is 400 kg, will be:
Given, u = 54 km/h
= 54 x 5/18 m/s
= 15 m/s
V = 0 and t = 5 s.
Retardation, a = v – u/t = 0 – 15/5 = – 3 m/s ²
Avg retardation force,
F = 400 x 3
= 1200 N
Share
(A) 1200 N