# A Train starting from rest attains a velocity of 90 km/h in 2 min, then the distance travelled by the train for attaining this velocity is:

Class 9th Science Session 2022-23

Class 9 Science Terminal Exams MCQ Solutions

9th Science Terminal Exam Based MCQ Extra Questions

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(A) 1.5 km

Given, u = 0, v = 90 km/h = 90 x 5/18 = 25 m/s

From the equation of motion,

v = u + at

a = v/t

or, 25/2×60

or, 5/24 m/s²

Distance covered is:

S = ut + 1/2 at²

= 0 + 1/2 x 5/24 x (120)²

= 1/2 x 5/24 x 120 x 120

= 1500 m

= 1.5 km