(A) 1.5 km Given, u = 0, v = 90 km/h = 90 x 5/18 = 25 m/s From the equation of motion, v = u + at a = v/t or, 25/2x60 or, 5/24 m/s² Distance covered is: S = ut + 1/2 at² = 0 + 1/2 x 5/24 x (120)² = 1/2 x 5/24 x 120 x 120 = 1500 m = 1.5 km

(A) 1.5 km
Given, u = 0, v = 90 km/h = 90 x 5/18 = 25 m/s
From the equation of motion,
v = u + at
a = v/t
or, 25/2×60
or, 5/24 m/s²
Distance covered is:
S = ut + 1/2 at²
= 0 + 1/2 x 5/24 x (120)²
= 1/2 x 5/24 x 120 x 120
= 1500 m
= 1.5 km

## A Train starting from rest attains a velocity of 90 km/h in 2 min, then the distance travelled by the train for attaining this velocity is:

(A) 1.5 km Given, u = 0, v = 90 km/h = 90 x 5/18 = 25 m/s From the equation of motion, v = u + at a = v/t or, 25/2x60 or, 5/24 m/s² Distance covered is: S = ut + 1/2 at² = 0 + 1/2 x 5/24 x (120)² = 1/2 x 5/24 x 120 x 120 = 1500 m = 1.5 km

(A) 1.5 km

See lessGiven, u = 0, v = 90 km/h = 90 x 5/18 = 25 m/s

From the equation of motion,

v = u + at

a = v/t

or, 25/2×60

or, 5/24 m/s²

Distance covered is:

S = ut + 1/2 at²

= 0 + 1/2 x 5/24 x (120)²

= 1/2 x 5/24 x 120 x 120

= 1500 m

= 1.5 km