To identify three primes less than 30 whose product is 1955, test combinations of primes: • Start with 5×13 = 635 • Then 65×29 = 1955 Thus, the primes are 5, 13, and 29. Each number is prime (only divisible by 1 and itself), and their product equals 1955. No other set of three primes under 30 meetsRead more
To identify three primes less than 30 whose product is 1955, test combinations of primes:
• Start with 5×13 = 635
• Then 65×29 = 1955
Thus, the primes are 5, 13, and 29. Each number is prime (only divisible by 1 and itself), and their product equals 1955. No other set of three primes under 30 meets these conditions, confirming these as the solution.
इडली वड़ा गेम में इसे 3 और 5 दोनों के गुणज पर बोला जाता है। 3 और 5 का LCM 15 है। इनके गुणज हैं: 15, 30, 45, 60, 75, 90, 105, 120, 135, और 150। जब 10वां गुणज गिना जाता है, तो वह 15 × 10 = 150 है। इसलिए, इडली वड़ा 10वीं बार 150 पर बोला जाता है। For more NCERT Solutions for Class 6 Math Chapter 5 PrimeRead more
इडली वड़ा गेम में इसे 3 और 5 दोनों के गुणज पर बोला जाता है। 3 और 5 का LCM 15 है। इनके गुणज हैं: 15, 30, 45, 60, 75, 90, 105, 120, 135, और 150। जब 10वां गुणज गिना जाता है, तो वह 15 × 10 = 150 है। इसलिए, इडली वड़ा 10वीं बार 150 पर बोला जाता है।
In the idli-vada game, players say 'idli-vada' for numbers that are multiples of both 3 and 5. These numbers include 15, 30, 45, 60, 75, 90, 105, 120, 135, and 150. Therefore, when counting the 10th such occurrence, the number is 150. This pattern arises from the least common multiple (LCM) of 3 andRead more
In the idli-vada game, players say ‘idli-vada’ for numbers that are multiples of both 3 and 5. These numbers include 15, 30, 45, 60, 75, 90, 105, 120, 135, and 150. Therefore, when counting the 10th such occurrence, the number is 150. This pattern arises from the least common multiple (LCM) of 3 and 5, which is 15, repeating every cycle.
In the game, ‘idli’ is said for multiples of 3, which occur 30 times from 3 to 90. ‘Vada’ is said for multiples of 5, totaling 18 times. Numbers like 15, 30, 45, 60, 75, and 90 overlap both categories, so ‘idli-vada’ is said 6 times for these multiples. Since ‘idli’ and ‘vada’ overlap, the total uniRead more
In the game, ‘idli’ is said for multiples of 3, which occur 30 times from 3 to 90. ‘Vada’ is said for multiples of 5, totaling 18 times. Numbers like 15, 30, 45, 60, 75, and 90 overlap both categories, so ‘idli-vada’ is said 6 times for these multiples. Since ‘idli’ and ‘vada’ overlap, the total unique calls differ depending on whether these overlaps are included in both counts.
When playing till 900, ‘idli’ is called for multiples of 3, occurring 300 times (3 × 300 = 900). ‘Vada’ corresponds to multiples of 5, occurring 180 times (5 × 180 = 900). For ‘idli-vada,’ said for multiples of both 3 and 5 (LCM 15), there are 60 instances (15 × 60 = 900). The overlaps ensure no douRead more
When playing till 900, ‘idli’ is called for multiples of 3, occurring 300 times (3 × 300 = 900). ‘Vada’ corresponds to multiples of 5, occurring 180 times (5 × 180 = 900). For ‘idli-vada,’ said for multiples of both 3 and 5 (LCM 15), there are 60 instances (15 × 60 = 900). The overlaps ensure no double counting, and the counts follow the divisibility rules for these multiples within the range.
To reach both treasures at 14 and 36, the jump size must divide both numbers. The factors of 14 are 1, 2, 7, and 14; the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. The common factors are 1 and 2, making these valid jump sizes. Since the GCD is 2, it guarantees the smallest successful jump tRead more
To reach both treasures at 14 and 36, the jump size must divide both numbers. The factors of 14 are 1, 2, 7, and 14; the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. The common factors are 1 and 2, making these valid jump sizes. Since the GCD is 2, it guarantees the smallest successful jump that aligns perfectly with both treasures.
To find multiples of 40 between 310 and 410, divide the lower bound by 40 (310 ÷ 40 = 7.75) and round up to 8. Multiply 40 by 8 to get 320, the first multiple. Similarly, dividing the upper bound (410 ÷ 40 = 10.25) and rounding down to 10 gives 400 as the last multiple. The full sequence is 320, 360Read more
To find multiples of 40 between 310 and 410, divide the lower bound by 40 (310 ÷ 40 = 7.75) and round up to 8. Multiply 40 by 8 to get 320, the first multiple. Similarly, dividing the upper bound (410 ÷ 40 = 10.25) and rounding down to 10 gives 400 as the last multiple. The full sequence is 320, 360, and 400, as all are divisible by 40 and fall within the specified range.
The required number must meet three criteria: be less than 40, have 7 as a factor, and have a digit sum of 8. The multiples of 7 under 40 are 7, 14, 21, 28, and 35. Out of these, only 35 satisfies the digit sum condition (3 + 5 = 8). Its complete set of factors is 1, 5, 7, and 35. Thus, the answer iRead more
The required number must meet three criteria: be less than 40, have 7 as a factor, and have a digit sum of 8. The multiples of 7 under 40 are 7, 14, 21, 28, and 35. Out of these, only 35 satisfies the digit sum condition (3 + 5 = 8). Its complete set of factors is 1, 5, 7, and 35. Thus, the answer is 35, fulfilling all the stated conditions.
To solve, the number must be under 100, divisible by both 3 and 5, and its digits differ by 1. Numbers divisible by 3 and 5 have 15 as their least common multiple. Checking these, 15 fits perfectly, as its digits (1 and 5) meet the condition where one is exactly 1 more than the other. The factors ofRead more
To solve, the number must be under 100, divisible by both 3 and 5, and its digits differ by 1. Numbers divisible by 3 and 5 have 15 as their least common multiple. Checking these, 15 fits perfectly, as its digits (1 and 5) meet the condition where one is exactly 1 more than the other. The factors of 15 include 1, 3, 5, and 15, further verifying it meets all the criteria.
To determine the common factors of 20 and 28, list their factors. For 20, the factors are 1, 2, 4, 5, 10, and 20. For 28, the factors are 1, 2, 4, 7, 14, and 28. Comparing these, the common factors are 1, 2, and 4. These shared divisors show the numbers' overlap, with 4 being the greatest common divRead more
To determine the common factors of 20 and 28, list their factors. For 20, the factors are 1, 2, 4, 5, 10, and 20. For 28, the factors are 1, 2, 4, 7, 14, and 28. Comparing these, the common factors are 1, 2, and 4. These shared divisors show the numbers’ overlap, with 4 being the greatest common divisor (GCD) and thus the largest number that divides both evenly.
What three prime numbers or less than 30 whose product is 1955?
To identify three primes less than 30 whose product is 1955, test combinations of primes: • Start with 5×13 = 635 • Then 65×29 = 1955 Thus, the primes are 5, 13, and 29. Each number is prime (only divisible by 1 and itself), and their product equals 1955. No other set of three primes under 30 meetsRead more
To identify three primes less than 30 whose product is 1955, test combinations of primes:
• Start with 5×13 = 635
• Then 65×29 = 1955
Thus, the primes are 5, 13, and 29. Each number is prime (only divisible by 1 and itself), and their product equals 1955. No other set of three primes under 30 meets these conditions, confirming these as the solution.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
इडली वड़ा किस नंबर पर 10 बार बोला जाता है?
इडली वड़ा गेम में इसे 3 और 5 दोनों के गुणज पर बोला जाता है। 3 और 5 का LCM 15 है। इनके गुणज हैं: 15, 30, 45, 60, 75, 90, 105, 120, 135, और 150। जब 10वां गुणज गिना जाता है, तो वह 15 × 10 = 150 है। इसलिए, इडली वड़ा 10वीं बार 150 पर बोला जाता है। For more NCERT Solutions for Class 6 Math Chapter 5 PrimeRead more
इडली वड़ा गेम में इसे 3 और 5 दोनों के गुणज पर बोला जाता है। 3 और 5 का LCM 15 है। इनके गुणज हैं: 15, 30, 45, 60, 75, 90, 105, 120, 135, और 150। जब 10वां गुणज गिना जाता है, तो वह 15 × 10 = 150 है। इसलिए, इडली वड़ा 10वीं बार 150 पर बोला जाता है।
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
At what number is idli-vada said for the 10th time?
In the idli-vada game, players say 'idli-vada' for numbers that are multiples of both 3 and 5. These numbers include 15, 30, 45, 60, 75, 90, 105, 120, 135, and 150. Therefore, when counting the 10th such occurrence, the number is 150. This pattern arises from the least common multiple (LCM) of 3 andRead more
In the idli-vada game, players say ‘idli-vada’ for numbers that are multiples of both 3 and 5. These numbers include 15, 30, 45, 60, 75, 90, 105, 120, 135, and 150. Therefore, when counting the 10th such occurrence, the number is 150. This pattern arises from the least common multiple (LCM) of 3 and 5, which is 15, repeating every cycle.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
How many times would children say idli, vada, and idli-vada in a game played till 90?
In the game, ‘idli’ is said for multiples of 3, which occur 30 times from 3 to 90. ‘Vada’ is said for multiples of 5, totaling 18 times. Numbers like 15, 30, 45, 60, 75, and 90 overlap both categories, so ‘idli-vada’ is said 6 times for these multiples. Since ‘idli’ and ‘vada’ overlap, the total uniRead more
In the game, ‘idli’ is said for multiples of 3, which occur 30 times from 3 to 90. ‘Vada’ is said for multiples of 5, totaling 18 times. Numbers like 15, 30, 45, 60, 75, and 90 overlap both categories, so ‘idli-vada’ is said 6 times for these multiples. Since ‘idli’ and ‘vada’ overlap, the total unique calls differ depending on whether these overlaps are included in both counts.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
If the game is played till 900, how many times would children say idli, vada, and idli-vada?
When playing till 900, ‘idli’ is called for multiples of 3, occurring 300 times (3 × 300 = 900). ‘Vada’ corresponds to multiples of 5, occurring 180 times (5 × 180 = 900). For ‘idli-vada,’ said for multiples of both 3 and 5 (LCM 15), there are 60 instances (15 × 60 = 900). The overlaps ensure no douRead more
When playing till 900, ‘idli’ is called for multiples of 3, occurring 300 times (3 × 300 = 900). ‘Vada’ corresponds to multiples of 5, occurring 180 times (5 × 180 = 900). For ‘idli-vada,’ said for multiples of both 3 and 5 (LCM 15), there are 60 instances (15 × 60 = 900). The overlaps ensure no double counting, and the counts follow the divisibility rules for these multiples within the range.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
What are the jump sizes that will reach both treasures at 14 and 36?
To reach both treasures at 14 and 36, the jump size must divide both numbers. The factors of 14 are 1, 2, 7, and 14; the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. The common factors are 1 and 2, making these valid jump sizes. Since the GCD is 2, it guarantees the smallest successful jump tRead more
To reach both treasures at 14 and 36, the jump size must divide both numbers. The factors of 14 are 1, 2, 7, and 14; the factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. The common factors are 1 and 2, making these valid jump sizes. Since the GCD is 2, it guarantees the smallest successful jump that aligns perfectly with both treasures.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
Find all multiples of 40 that lie between 310 and 410.
To find multiples of 40 between 310 and 410, divide the lower bound by 40 (310 ÷ 40 = 7.75) and round up to 8. Multiply 40 by 8 to get 320, the first multiple. Similarly, dividing the upper bound (410 ÷ 40 = 10.25) and rounding down to 10 gives 400 as the last multiple. The full sequence is 320, 360Read more
To find multiples of 40 between 310 and 410, divide the lower bound by 40 (310 ÷ 40 = 7.75) and round up to 8. Multiply 40 by 8 to get 320, the first multiple. Similarly, dividing the upper bound (410 ÷ 40 = 10.25) and rounding down to 10 gives 400 as the last multiple. The full sequence is 320, 360, and 400, as all are divisible by 40 and fall within the specified range.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
Who am I? a) I am a number less than 40. One of my factors is 7. The sum of my digits is 8.
The required number must meet three criteria: be less than 40, have 7 as a factor, and have a digit sum of 8. The multiples of 7 under 40 are 7, 14, 21, 28, and 35. Out of these, only 35 satisfies the digit sum condition (3 + 5 = 8). Its complete set of factors is 1, 5, 7, and 35. Thus, the answer iRead more
The required number must meet three criteria: be less than 40, have 7 as a factor, and have a digit sum of 8. The multiples of 7 under 40 are 7, 14, 21, 28, and 35. Out of these, only 35 satisfies the digit sum condition (3 + 5 = 8). Its complete set of factors is 1, 5, 7, and 35. Thus, the answer is 35, fulfilling all the stated conditions.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
Who am I? b) I am a number less than 100. Two of my factors are 3 and 5. One of my digits is 1 more than the other.
To solve, the number must be under 100, divisible by both 3 and 5, and its digits differ by 1. Numbers divisible by 3 and 5 have 15 as their least common multiple. Checking these, 15 fits perfectly, as its digits (1 and 5) meet the condition where one is exactly 1 more than the other. The factors ofRead more
To solve, the number must be under 100, divisible by both 3 and 5, and its digits differ by 1. Numbers divisible by 3 and 5 have 15 as their least common multiple. Checking these, 15 fits perfectly, as its digits (1 and 5) meet the condition where one is exactly 1 more than the other. The factors of 15 include 1, 3, 5, and 15, further verifying it meets all the criteria.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/
Find the common factors of: a) 20 and 28
To determine the common factors of 20 and 28, list their factors. For 20, the factors are 1, 2, 4, 5, 10, and 20. For 28, the factors are 1, 2, 4, 7, 14, and 28. Comparing these, the common factors are 1, 2, and 4. These shared divisors show the numbers' overlap, with 4 being the greatest common divRead more
To determine the common factors of 20 and 28, list their factors. For 20, the factors are 1, 2, 4, 5, 10, and 20. For 28, the factors are 1, 2, 4, 7, 14, and 28. Comparing these, the common factors are 1, 2, and 4. These shared divisors show the numbers’ overlap, with 4 being the greatest common divisor (GCD) and thus the largest number that divides both evenly.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/