To calculate the area of each figure, divide the irregular shapes into smaller rectangles and triangles. Use the formula for the area of a rectangle (length multiplied by width) for the rectangular sections. For the triangular sections, apply the formula (base multiplied by height divided by 2). SumRead more
To calculate the area of each figure, divide the irregular shapes into smaller rectangles and triangles. Use the formula for the area of a rectangle (length multiplied by width) for the rectangular sections. For the triangular sections, apply the formula (base multiplied by height divided by 2). Sum the areas of all the sections to determine the total area of the figure. Using grid paper can simplify this process by counting squares and dividing accordingly.
Calculate the areas of both rectangles: Area 1 = 5 × 10 = 50 square meters Area 2 = 2 × 7 = 14 square meters Add them together to get the total area: Total Area = 50 + 14 = 64 square meters. A square with dimensions 8 meters × 8 meters satisfies this, as: Area = 8 × 8 = 64 square meters. Thus, the dRead more
Calculate the areas of both rectangles:
Area 1 = 5 × 10 = 50 square meters
Area 2 = 2 × 7 = 14 square meters
Add them together to get the total area:
Total Area = 50 + 14 = 64 square meters.
A square with dimensions 8 meters × 8 meters satisfies this, as:
Area = 8 × 8 = 64 square meters.
Thus, the dimensions of the required rectangle are 8 m × 8 m.
Use the formula for the area of a rectangle: Area = Length × Width. Here, Area = 1000 square meters, and Length = 50 meters. Rearrange to find the width: Width = Area ÷ Length Width = 1000 ÷ 50 = 20 meters. Thus, the width of the garden is 20 meters. For more NCERT Solutions for Class 6 Math ChapterRead more
Use the formula for the area of a rectangle:
Area = Length × Width.
Here, Area = 1000 square meters, and Length = 50 meters. Rearrange to find the width:
Width = Area ÷ Length
Width = 1000 ÷ 50 = 20 meters.
Thus, the width of the garden is 20 meters.
First, calculate the area of the room: Area of room = 5 × 4 = 20 square meters. Next, calculate the area of the square carpet: Area of carpet = 3 × 3 = 9 square meters. The area that is not carpeted is: Uncovered area = Area of room − Area of carpet Uncovered area = 20 − 9 = 11 square meters. Thus,Read more
First, calculate the area of the room:
Area of room = 5 × 4 = 20 square meters.
Next, calculate the area of the square carpet:
Area of carpet = 3 × 3 = 9 square meters.
The area that is not carpeted is:
Uncovered area = Area of room − Area of carpet
Uncovered area = 20 − 9 = 11 square meters.
Thus, 11 square meters of the floor remains uncovered.
First, calculate the total area of the garden: Garden area = 15 × 12 = 180 square meters. Next, calculate the area of one flower bed: Area of one flower bed = 2 × 1 = 2 square meters. For four flower beds: Total flower bed area = 4 × 2 = 8 square meters. The area available for laying a lawn is: RemaRead more
First, calculate the total area of the garden:
Garden area = 15 × 12 = 180 square meters.
Next, calculate the area of one flower bed:
Area of one flower bed = 2 × 1 = 2 square meters.
For four flower beds:
Total flower bed area = 4 × 2 = 8 square meters.
The area available for laying a lawn is:
Remaining area = Garden area − Flower bed area
Remaining area = 180 − 8 = 172 square meters.
Find the areas of the figures below by dividing them into rectangles and triangles.
To calculate the area of each figure, divide the irregular shapes into smaller rectangles and triangles. Use the formula for the area of a rectangle (length multiplied by width) for the rectangular sections. For the triangular sections, apply the formula (base multiplied by height divided by 2). SumRead more
To calculate the area of each figure, divide the irregular shapes into smaller rectangles and triangles. Use the formula for the area of a rectangle (length multiplied by width) for the rectangular sections. For the triangular sections, apply the formula (base multiplied by height divided by 2). Sum the areas of all the sections to determine the total area of the figure. Using grid paper can simplify this process by counting squares and dividing accordingly.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Give the dimensions of a rectangle whose area is the sum of the areas of these two rectangles having measurements: 5 m × 10 m and 2 m × 7 m.
Calculate the areas of both rectangles: Area 1 = 5 × 10 = 50 square meters Area 2 = 2 × 7 = 14 square meters Add them together to get the total area: Total Area = 50 + 14 = 64 square meters. A square with dimensions 8 meters × 8 meters satisfies this, as: Area = 8 × 8 = 64 square meters. Thus, the dRead more
Calculate the areas of both rectangles:
Area 1 = 5 × 10 = 50 square meters
Area 2 = 2 × 7 = 14 square meters
Add them together to get the total area:
Total Area = 50 + 14 = 64 square meters.
A square with dimensions 8 meters × 8 meters satisfies this, as:
Area = 8 × 8 = 64 square meters.
Thus, the dimensions of the required rectangle are 8 m × 8 m.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
The area of a rectangular garden that is 50 m long is 1000 sq m. Find the width of the garden.
Use the formula for the area of a rectangle: Area = Length × Width. Here, Area = 1000 square meters, and Length = 50 meters. Rearrange to find the width: Width = Area ÷ Length Width = 1000 ÷ 50 = 20 meters. Thus, the width of the garden is 20 meters. For more NCERT Solutions for Class 6 Math ChapterRead more
Use the formula for the area of a rectangle:
Area = Length × Width.
Here, Area = 1000 square meters, and Length = 50 meters. Rearrange to find the width:
Width = Area ÷ Length
Width = 1000 ÷ 50 = 20 meters.
Thus, the width of the garden is 20 meters.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
The floor of a room is 5 m long and 4 m wide. A square carpet whose sides are 3 m in length is laid on the floor. Find the area that is not carpeted.
First, calculate the area of the room: Area of room = 5 × 4 = 20 square meters. Next, calculate the area of the square carpet: Area of carpet = 3 × 3 = 9 square meters. The area that is not carpeted is: Uncovered area = Area of room − Area of carpet Uncovered area = 20 − 9 = 11 square meters. Thus,Read more
First, calculate the area of the room:
Area of room = 5 × 4 = 20 square meters.
Next, calculate the area of the square carpet:
Area of carpet = 3 × 3 = 9 square meters.
The area that is not carpeted is:
Uncovered area = Area of room − Area of carpet
Uncovered area = 20 − 9 = 11 square meters.
Thus, 11 square meters of the floor remains uncovered.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/
Four flower beds having sides 2 m long and 1 m wide are dug at the four corners of a garden that is 15 m long and 12 m wide. How much area is now available for laying down a lawn?
First, calculate the total area of the garden: Garden area = 15 × 12 = 180 square meters. Next, calculate the area of one flower bed: Area of one flower bed = 2 × 1 = 2 square meters. For four flower beds: Total flower bed area = 4 × 2 = 8 square meters. The area available for laying a lawn is: RemaRead more
First, calculate the total area of the garden:
Garden area = 15 × 12 = 180 square meters.
Next, calculate the area of one flower bed:
Area of one flower bed = 2 × 1 = 2 square meters.
For four flower beds:
Total flower bed area = 4 × 2 = 8 square meters.
The area available for laying a lawn is:
Remaining area = Garden area − Flower bed area
Remaining area = 180 − 8 = 172 square meters.
For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
See lesshttps://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/