1. The area of the blue rectangle is exactly equal to the area of the yellow triangle. The reason lies in how the yellow triangle is derived. It is formed by dividing the blue rectangle into two equal halves along the diagonal. Since both triangles created this way are congruent, each of their areas eqRead more

    The area of the blue rectangle is exactly equal to the area of the yellow triangle. The reason lies in how the yellow triangle is derived. It is formed by dividing the blue rectangle into two equal halves along the diagonal. Since both triangles created this way are congruent, each of their areas equals half of the rectangle’s area, ensuring their equivalence.

    For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/

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  2. The relationship between the blue rectangle and the yellow triangle is based on their areas. The yellow triangle represents half the area of the blue rectangle, as it is formed by dividing the rectangle along its diagonal. This division results in two equal triangles, each having an area equal to haRead more

    The relationship between the blue rectangle and the yellow triangle is based on their areas. The yellow triangle represents half the area of the blue rectangle, as it is formed by dividing the rectangle along its diagonal. This division results in two equal triangles, each having an area equal to half the rectangle. Hence, the triangle’s area is directly proportional to that of the rectangle, maintaining the ratio of 1:2.

    For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/

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  3. To find the area of triangle BAD, first calculate the area of rectangle ABCD by multiplying its length and width. The diagonal divides the rectangle into two equal triangles. Therefore, the area of triangle BAD is half the total area of rectangle ABCD. Using grid paper, count the total number of squRead more

    To find the area of triangle BAD, first calculate the area of rectangle ABCD by multiplying its length and width. The diagonal divides the rectangle into two equal triangles. Therefore, the area of triangle BAD is half the total area of rectangle ABCD. Using grid paper, count the total number of squares in the rectangle, and divide this count by 2 to determine the area of the triangle, confirming it is half the rectangle.

    For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/

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  4. To find the area of triangle ABE, divide it into two smaller triangles, AEF and BEF. Each of these smaller triangles is half the area of their respective rectangles (AFED and BFEC). By adding these two areas, you get the total area of triangle ABE. Since these smaller triangles together represent haRead more

    To find the area of triangle ABE, divide it into two smaller triangles, AEF and BEF. Each of these smaller triangles is half the area of their respective rectangles (AFED and BFEC). By adding these two areas, you get the total area of triangle ABE. Since these smaller triangles together represent half of the rectangle ABCD, the total area of triangle ABE equals half the area of rectangle ABCD. This calculation is verified using grid paper.

    For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/

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  5. The conclusion is that the diagonal of a rectangle divides it into two triangles of equal area, with each triangle's area being half the total area of the rectangle. When additional triangles are formed by further divisions within the rectangle, their areas can also be calculated as fractions of smaRead more

    The conclusion is that the diagonal of a rectangle divides it into two triangles of equal area, with each triangle’s area being half the total area of the rectangle. When additional triangles are formed by further divisions within the rectangle, their areas can also be calculated as fractions of smaller rectangles. This relationship between triangles and rectangles remains consistent regardless of the rectangle’s size or the dimensions of the divided sections.

    For more NCERT Solutions for Class 6 Math Chapter 6 Perimeter and Area Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-6/

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