4u² + 8u = 4u² +8u = 4u(u + 2) The value of 4u² + 8u is zero if 4u = 0 or u + 2 = 0. ⇒ u = 0 or u = -2. Therefore, the zeroes of 4u² + 8u are 0 and -2. Now, Sum of zeroes = 0 + (-2) = -2 = -(8)/4 = -(Coficient of u)/Cofficient of u²) Product of zeroes = 0 x (-2) = 0 = 0/4 = (Constant term)/(CofficieRead more
4u² + 8u
= 4u² +8u
= 4u(u + 2)
The value of 4u² + 8u is zero if 4u = 0 or u + 2 = 0.
⇒ u = 0 or u = -2.
Therefore, the zeroes of 4u² + 8u are 0 and -2.
Now, Sum of zeroes = 0 + (-2) = -2 = -(8)/4 = -(Coficient of u)/Cofficient of u²)
Product of zeroes = 0 x (-2) = 0 = 0/4 = (Constant term)/(Cofficient of u²)
Here is the Video Explanation 😀👇
The study of polynomials can be beneficial to students by helping them develop important mathematical skills, understand real-world applications, prepare them for further study, and improve their problem-solving skills.
t² - 15 = t² - (√15)² = (t + √15)(t - √15) The value of t² - 15 is zero if t + √15 = 0 or t - √15 = 0. ⇒ x = - √15 or x = √15. Therefore, the zeroes of t² - 15 are - √15 and √15. Now, Sum of zeroes = -√15 + √15 = 0 = -(0)/1 = -(Cofficient of t)/(Cofficient of t²) Product of zeroes = (-√15) x √15 = -Read more
t² – 15
= t² – (√15)²
= (t + √15)(t – √15)
The value of t² – 15 is zero if t + √15 = 0 or t – √15 = 0.
⇒ x = – √15 or x = √15.
Therefore, the zeroes of t² – 15 are – √15 and √15.
Now, Sum of zeroes = -√15 + √15 = 0 = -(0)/1 = -(Cofficient of t)/(Cofficient of t²)
Product of zeroes = (-√15) x √15 = -15 = -15/1 (Constant term)/(Cofticient of t²)
Resources can be classified based on their origin, which refers to where they come from or how they are obtained. Some common categories of resources based on their origin include: Natural resources: These are resources that are found in nature and are not originated by humans. Examples include mineRead more
Resources can be classified based on their origin, which refers to where they come from or how they are obtained. Some common categories of resources based on their origin include:
Natural resources: These are resources that are found in nature and are not originated by humans. Examples include minerals, timber, water, and air.
Man-made resources: These are resources that are originated by humans using raw materials or other resources. Examples include manufactured goods, such as cars, computers, and appliances.
Renewable resources: These are resources that can be replenished naturally over time. Examples include solar energy, wind energy, and hydroelectric power.
Nonrenewable resources: These are resources that are finite and cannot be replaced once they are used up. Examples include fossil fuels (such as coal, oil, and natural gas) and minerals.
General Knowledge, or GK, refers to a broad range of knowledge about various topics, including history, geography, science, literature, and current events. GK can help students develop a curiosity about the world around them and a desire to learn more about a wide range of topics. Encourage studentsRead more
General Knowledge, or GK, refers to a broad range of knowledge about various topics, including history, geography, science, literature, and current events. GK can help students develop a curiosity about the world around them and a desire to learn more about a wide range of topics. Encourage students to read about a variety of topics, including news, science, history, and current events. There are many educational games and quizzes available online that can help students learn about GK in a fun and engaging way. Encourage students to participate in discussions about current events and other topics related to GK.
It is not necessary for class 2 students to learn GK, but it can be a beneficial and enjoyable activity for students who are interested in learning about a wide range of topics.
(i) 135 and 225 Since 225 > 135, we apply the division lemma to 225 and 135 to obtain 225 = 135 × 1 + 90 Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain 135 = 90 × 1 + 45 We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain 90 = 2Read more
(i) 135 and 225
Since 225 > 135, we apply the division lemma to 225 and 135 to obtain
225 = 135 × 1 + 90
Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain
135 = 90 × 1 + 45
We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain 90 = 2 × 45 + 0
Since the remainder is zero, the process stops.
Since the divisor at this stage is 45, therefore, the HCF of 135 and 225 is 45.
196 and 38220 Since 38220 > 196, we apply the division lemma to 38220 and 196 to obtain 38220 = 196 × 195 + 0 Since the remainder is zero, the process stops. Since the divisor at this stage is 196, therefore, HCF of 196 and 38220 is 196. Here is the explanation Video see here=>
196 and 38220
Since 38220 > 196, we apply the division lemma to 38220 and 196 to obtain
38220 = 196 × 195 + 0
Since the remainder is zero, the process stops.
Since the divisor at this stage is 196, therefore, HCF of 196 and 38220 is 196.
Numbers are of two types-prime and composite. Prime numbers can be divided by 1 and only itself, whereas composite numbers have factors other than 1 and itself. It can be observed that: 7 x 11 x 13 + 13 = 13 x (7 x 11 + 1) = 13 x (77 + 1) = 13 x 78 = 13 x 13 x 6 The given expression has 6 and 13 asRead more
Numbers are of two types-prime and composite. Prime numbers can be divided by 1 and only itself, whereas composite numbers have factors other than 1 and itself.
It can be observed that:
7 x 11 x 13 + 13 = 13 x (7 x 11 + 1) = 13 x (77 + 1)
= 13 x 78
= 13 x 13 x 6
The given expression has 6 and 13 as its factors. Therefore, it is a composite number.
7 x 6 x 5 x 4 x 3 x 2 x 1 + 5 = 5 x (7 x 6 x 4 x 3 x 2 x 1 + 1)
= 5 x (1008 + 1)
= 5 x 1009
1009 cannot be factorised further. Therefore, the given expression has 5 and 1009 as its factors. Hence, it isa composite number.
I'm glad to hear that your younger brother is doing well in math and that you are looking for resources to help him continue to succeed. NCERT solutions are a great resource for students, as they provide detailed explanations of math concepts and problem-solving strategies. There are many other resoRead more
I’m glad to hear that your younger brother is doing well in math and that you are looking for resources to help him continue to succeed. NCERT solutions are a great resource for students, as they provide detailed explanations of math concepts and problem-solving strategies. There are many other resources available that can help your brother learn math concepts and practice problem-solving skills. Encourage your brother to ask questions and seek help when he is struggling with a math concept. This will help him to better understand the material and build a solid foundation of math skills.
Important topics in English grammar that Grade 1 students can be expected to learn are: > Students can learn to recognize and read letters of the alphabet and basic sight words such as "the," "a," and "is." > They can learn about basic sentence structure, such as subject, verb and object. >Read more
Important topics in English grammar that Grade 1 students can be expected to learn are:
> Students can learn to recognize and read letters of the alphabet and basic sight words such as
“the,” “a,” and “is.”
> They can learn about basic sentence structure, such as subject, verb and object.
> They can also learn about simple sentences and punctuation marks.
Whether to study online or offline depends on the learning preferences of each student. Some students may prefer the structure and guidance of an offline classroom, while others may prefer the convenience and flexibility of online learning. It is important to find a study method that works best for the student.
For more information => https://www.tiwariacademy.com/ncert-solutions/class-1/english/grammar/
Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. 4u² + 8u.
4u² + 8u = 4u² +8u = 4u(u + 2) The value of 4u² + 8u is zero if 4u = 0 or u + 2 = 0. ⇒ u = 0 or u = -2. Therefore, the zeroes of 4u² + 8u are 0 and -2. Now, Sum of zeroes = 0 + (-2) = -2 = -(8)/4 = -(Coficient of u)/Cofficient of u²) Product of zeroes = 0 x (-2) = 0 = 0/4 = (Constant term)/(CofficieRead more
4u² + 8u
= 4u² +8u
= 4u(u + 2)
The value of 4u² + 8u is zero if 4u = 0 or u + 2 = 0.
⇒ u = 0 or u = -2.
Therefore, the zeroes of 4u² + 8u are 0 and -2.
Now, Sum of zeroes = 0 + (-2) = -2 = -(8)/4 = -(Coficient of u)/Cofficient of u²)
Product of zeroes = 0 x (-2) = 0 = 0/4 = (Constant term)/(Cofficient of u²)
Here is the Video Explanation 😀👇
See lessThe study of polynomials can be beneficial to students by helping them develop important mathematical skills, understand real-world applications, prepare them for further study, and improve their problem-solving skills.
Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. t² – 15.
t² - 15 = t² - (√15)² = (t + √15)(t - √15) The value of t² - 15 is zero if t + √15 = 0 or t - √15 = 0. ⇒ x = - √15 or x = √15. Therefore, the zeroes of t² - 15 are - √15 and √15. Now, Sum of zeroes = -√15 + √15 = 0 = -(0)/1 = -(Cofficient of t)/(Cofficient of t²) Product of zeroes = (-√15) x √15 = -Read more
t² – 15
= t² – (√15)²
= (t + √15)(t – √15)
The value of t² – 15 is zero if t + √15 = 0 or t – √15 = 0.
⇒ x = – √15 or x = √15.
Therefore, the zeroes of t² – 15 are – √15 and √15.
Now, Sum of zeroes = -√15 + √15 = 0 = -(0)/1 = -(Cofficient of t)/(Cofficient of t²)
Product of zeroes = (-√15) x √15 = -15 = -15/1 (Constant term)/(Cofticient of t²)
See here👇
See lessSample Paper for Class 9th Session 2022 – 2023
Check it out => https://www.tiwariacademy.com/ncert-solutions/class-9/
Check it out => https://www.tiwariacademy.com/ncert-solutions/class-9/
See lessDistinguish the resources on the basic of origin?
Resources can be classified based on their origin, which refers to where they come from or how they are obtained. Some common categories of resources based on their origin include: Natural resources: These are resources that are found in nature and are not originated by humans. Examples include mineRead more
Resources can be classified based on their origin, which refers to where they come from or how they are obtained. Some common categories of resources based on their origin include:
Natural resources: These are resources that are found in nature and are not originated by humans. Examples include minerals, timber, water, and air.
Man-made resources: These are resources that are originated by humans using raw materials or other resources. Examples include manufactured goods, such as cars, computers, and appliances.
Renewable resources: These are resources that can be replenished naturally over time. Examples include solar energy, wind energy, and hydroelectric power.
Nonrenewable resources: These are resources that are finite and cannot be replaced once they are used up. Examples include fossil fuels (such as coal, oil, and natural gas) and minerals.
For NCERT solution click here=>
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-10/social-science/geography/chapter-1/
What are the benefits of General Knowledge GK in Class 2?
General Knowledge, or GK, refers to a broad range of knowledge about various topics, including history, geography, science, literature, and current events. GK can help students develop a curiosity about the world around them and a desire to learn more about a wide range of topics. Encourage studentsRead more
General Knowledge, or GK, refers to a broad range of knowledge about various topics, including history, geography, science, literature, and current events. GK can help students develop a curiosity about the world around them and a desire to learn more about a wide range of topics. Encourage students to read about a variety of topics, including news, science, history, and current events. There are many educational games and quizzes available online that can help students learn about GK in a fun and engaging way. Encourage students to participate in discussions about current events and other topics related to GK.
It is not necessary for class 2 students to learn GK, but it can be a beneficial and enjoyable activity for students who are interested in learning about a wide range of topics.
For free study material click here =>
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-2/gk/
Use Euclid’s division algorithm to find the HCF of : 135 and 225
(i) 135 and 225 Since 225 > 135, we apply the division lemma to 225 and 135 to obtain 225 = 135 × 1 + 90 Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain 135 = 90 × 1 + 45 We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain 90 = 2Read more
(i) 135 and 225
Since 225 > 135, we apply the division lemma to 225 and 135 to obtain
225 = 135 × 1 + 90
Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain
135 = 90 × 1 + 45
We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain 90 = 2 × 45 + 0
Since the remainder is zero, the process stops.
Since the divisor at this stage is 45, therefore, the HCF of 135 and 225 is 45.
For better explanation see here =>
See lessUse Euclid’s division algorithm to find the HCF of : 196 and 38220.
196 and 38220 Since 38220 > 196, we apply the division lemma to 38220 and 196 to obtain 38220 = 196 × 195 + 0 Since the remainder is zero, the process stops. Since the divisor at this stage is 196, therefore, HCF of 196 and 38220 is 196. Here is the explanation Video see here=>
196 and 38220
Since 38220 > 196, we apply the division lemma to 38220 and 196 to obtain
38220 = 196 × 195 + 0
Since the remainder is zero, the process stops.
Since the divisor at this stage is 196, therefore, HCF of 196 and 38220 is 196.
Here is the explanation Video see here=>
See lessExplain why 7 × 11 × 13 + 13 and 7 × 6 × 5 × 4 × 3 × 2 × 1 + 5 are composite numbers.
Numbers are of two types-prime and composite. Prime numbers can be divided by 1 and only itself, whereas composite numbers have factors other than 1 and itself. It can be observed that: 7 x 11 x 13 + 13 = 13 x (7 x 11 + 1) = 13 x (77 + 1) = 13 x 78 = 13 x 13 x 6 The given expression has 6 and 13 asRead more
Numbers are of two types-prime and composite. Prime numbers can be divided by 1 and only itself, whereas composite numbers have factors other than 1 and itself.
It can be observed that:
7 x 11 x 13 + 13 = 13 x (7 x 11 + 1) = 13 x (77 + 1)
= 13 x 78
= 13 x 13 x 6
The given expression has 6 and 13 as its factors. Therefore, it is a composite number.
7 x 6 x 5 x 4 x 3 x 2 x 1 + 5 = 5 x (7 x 6 x 4 x 3 x 2 x 1 + 1)
= 5 x (1008 + 1)
= 5 x 1009
1009 cannot be factorised further. Therefore, the given expression has 5 and 1009 as its factors. Hence, it isa composite number.
For better explanation see here =>
See lessDo you have NCERT Solutions for Class 2 Maths?
I'm glad to hear that your younger brother is doing well in math and that you are looking for resources to help him continue to succeed. NCERT solutions are a great resource for students, as they provide detailed explanations of math concepts and problem-solving strategies. There are many other resoRead more
I’m glad to hear that your younger brother is doing well in math and that you are looking for resources to help him continue to succeed. NCERT solutions are a great resource for students, as they provide detailed explanations of math concepts and problem-solving strategies. There are many other resources available that can help your brother learn math concepts and practice problem-solving skills. Encourage your brother to ask questions and seek help when he is struggling with a math concept. This will help him to better understand the material and build a solid foundation of math skills.
Follow this link For Class 2 Math NCERT Solution =>
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-2/maths/
Who provides study material and English Grammar solutions for class 1 students?
Important topics in English grammar that Grade 1 students can be expected to learn are: > Students can learn to recognize and read letters of the alphabet and basic sight words such as "the," "a," and "is." > They can learn about basic sentence structure, such as subject, verb and object. >Read more
Important topics in English grammar that Grade 1 students can be expected to learn are:
> Students can learn to recognize and read letters of the alphabet and basic sight words such as
“the,” “a,” and “is.”
> They can learn about basic sentence structure, such as subject, verb and object.
> They can also learn about simple sentences and punctuation marks.
Whether to study online or offline depends on the learning preferences of each student. Some students may prefer the structure and guidance of an offline classroom, while others may prefer the convenience and flexibility of online learning. It is important to find a study method that works best for the student.
See lessFor more information => https://www.tiwariacademy.com/ncert-solutions/class-1/english/grammar/