1. Choice (a) is correct. Since cos 90° = 0  ⇒ cos 1° cos 2° cos 3° ..... cos 179° = 0. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-soRead more

    Choice (a) is correct. Since cos 90° = 0  ⇒ cos 1° cos 2° cos 3° ….. cos 179° = 0.
    This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.

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    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3

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  2. Choice (a) is correct. For a relation from A to B, first entry should belongs to set A and second entry B. This question related to Chapter 2 maths Class 11th NCERT. From the Chapter 2: Relations and Functions. Give answer according to your understanding. For more please visit here: https://www.tiwaRead more

    Choice (a) is correct. For a relation from A to B, first entry should belongs to set A and second entry B. This question related to Chapter 2 maths Class 11th NCERT. From the Chapter 2: Relations and Functions. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-2

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  3. Choice (a) is correct.  We have, n(A) = m and n(B) = n n(A × B) =n (A).n(B) =mn Number of subsets of A × B = 2ᵐⁿ Number of non-empty subsets of A × B = 2ᵐⁿ -1  Number of non-empty relation from A to B = 2ᵐⁿ -1 This question related to Chapter 2 maths Class 11th NCERT. From the Chapter 2: Relations aRead more

    Choice (a) is correct. 
    We have, n(A) = m and n(B) = n
    n(A × B) =n (A).n(B) =mn
    Number of subsets of A × B = 2ᵐⁿ
    Number of non-empty subsets of A × B = 2ᵐⁿ -1 
    Number of non-empty relation from A to B = 2ᵐⁿ -1
    This question related to Chapter 2 maths Class 11th NCERT. From the Chapter 2: Relations and Functions. Give answer according to your understanding.

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    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-2

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    • 28
  4. Choice (b) is correct.  We have, f(x) = √1 + x² f(y) = √1 + y² and f(xy) = √1 + (xy)² = √1 + x²y² f(x).f(y) = √1 + x². √1 + y² = √1 + x² + y² + x²y² √1+ x²y² ≤ √1 + x² + y² + x²y² f(xy) ≤ f(x)f(y) This question related to Chapter 2 maths Class 11th NCERT. From the Chapter 2: Relations and Functions.Read more

    Choice (b) is correct. 
    We have, f(x) = √1 + x²
    f(y) = √1 + y² and f(xy) = √1 + (xy)² = √1 + x²y²
    f(x).f(y) = √1 + x². √1 + y² = √1 + x² + y² + x²y²
    √1+ x²y² ≤ √1 + x² + y² + x²y²
    f(xy) ≤ f(x)f(y)
    This question related to Chapter 2 maths Class 11th NCERT. From the Chapter 2: Relations and Functions. Give answer according to your understanding.

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    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-2

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  5. Choice (a) is correct. We have f(x) = eˣ = g(x) = logₑ x Now, fg(x) = f(x)g(x) = eˣlogₑ x fg(1) = f(1)g(1) = e¹logₑ 1 = e × 0 = 0  This question related to Chapter 2 maths Class 11th NCERT. From the Chapter 2: Relations and Functions. Give answer according to your understanding. For more please visiRead more

    Choice (a) is correct. We have f(x) = eˣ = g(x) = logₑ x
    Now, fg(x) = f(x)g(x) = eˣlogₑ x
    fg(1) = f(1)g(1) = e¹logₑ 1 = e × 0 = 0 
    This question related to Chapter 2 maths Class 11th NCERT. From the Chapter 2: Relations and Functions. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-2

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