1. Choice (c) is correct.  ∣ z ∣ = 4  ⇒ ∣ x + iy ∣ = 4 ⇒ √x² + y² = 4  ⇒ x² + y² = 16 This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding. For more please visit here: https://www.tiwariacademRead more

    Choice (c) is correct. 
    ∣ z ∣ = 4  ⇒ ∣ x + iy ∣ = 4
    ⇒ √x² + y² = 4  ⇒ x² + y² = 16
    This question related to Chapter 4 maths Class 11th NCERT. From the Chapter 4: Complex Numbers and Quadratic Equations. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-4

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    • 17
  2. Choice (c) is correct.  As sec θ ≤ - 1 or sec θ ≥ 1, so sec θ cannot be equal to 1/2. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-sRead more

    Choice (c) is correct. 
    As sec θ ≤ – 1 or sec θ ≥ 1, so sec θ cannot be equal to 1/2.
    This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3

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    • 15
  3. Choice (b) is correct. As tangent function is negative in 2nd and 4th quadrants.  This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutRead more

    Choice (b) is correct. As tangent function is negative in 2nd and 4th quadrants. 
    This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3

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    • 33
  4. Choice (d) is correct. Given that , tan θ = 3 we know that, sec² θ = 1 + tan² θ  ⇒ sec² θ = 1 + 3² = 1 + 9 = 10 ⇒ cos² θ = 1/10 We know that sin² θ = 1 - cos² θ sin² θ = 1 - 1/10 = 10 - 1/10 = 9/10 ⇒ sin θ = ± √9/10 = ± 3/√10 ⇒ sin θ = -3√10 This question related to Chapter 3 maths Class 11th NCERT.Read more

    Choice (d) is correct. Given that , tan θ = 3
    we know that, sec² θ = 1 + tan² θ 
    ⇒ sec² θ = 1 + 3² = 1 + 9 = 10 ⇒ cos² θ = 1/10
    We know that sin² θ = 1 – cos² θ
    sin² θ = 1 – 1/10 = 10 – 1/10 = 9/10
    ⇒ sin θ = ± √9/10 = ± 3/√10 ⇒ sin θ = -3√10
    This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3

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    • 20
  5. Choice (b) is correct. We know that sine function is an increasing function in first quadrant and 1 radian = 57.296 degrees. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit hereRead more

    Choice (b) is correct. We know that sine function is an increasing function in first quadrant and 1 radian = 57.296 degrees. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3

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    • 19