Choice (a) is correct. Given that, f(x) = cos² x + sec² x We know that, A.M ≥ G.M (cos² x + sec ² x)/2 ≥ √cos² x. sec ² x ⇒ cos² x + sec ² x ≥ 2 ⇒ f(x) ≥ 2 This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understaRead more
Choice (a) is correct.
Given that, f(x) = cos² x + sec² x
We know that, A.M ≥ G.M
(cos² x + sec ² x)/2 ≥ √cos² x. sec ² x
⇒ cos² x + sec ² x ≥ 2
⇒ f(x) ≥ 2
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
Choice (d) is correct. cos 25° 35' cos 34° 25' - sin25° 35' sin 34°' 25' = cos(25° 35' + 34° 25') = cos 60° = 1/2 This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://wRead more
Choice (d) is correct.
cos 25° 35′ cos 34° 25′ – sin25° 35′ sin 34°’ 25′ = cos(25° 35′ + 34° 25′) = cos 60° = 1/2
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
Choice (a) is correct. Period of cosecant function 2π. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chaptRead more
Choice (a) is correct.
Period of cosecant function 2π. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
Choice (c) is correct. sin 64 π = sin (2π × 32 + 0) = sin 0 = 0 This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/matRead more
Choice (c) is correct.
sin 64 π = sin (2π × 32 + 0) = sin 0 = 0
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
Choice (b) is correct tan 1° tan 2° tan 3° ..... tan89° = (tan 1° tan89°) (tan 2° tan 88°)....(tan 44° tan 46°) tan 45° = {tan 1° tan (90° - 1°)} {tan 2° tan (90° - 2°)}..... {tan 44° tan (90° - 44°)} tan 45° = (tan 1° cot 1°) (tan 2° cot 2°).... (tan 44° cot 44°) tan45° = (1) (1)...(1)(1) = 1 ThisRead more
Choice (b) is correct tan 1° tan 2° tan 3° ….. tan89° = (tan 1° tan89°) (tan 2° tan 88°)….(tan 44° tan 46°) tan 45°
= {tan 1° tan (90° – 1°)} {tan 2° tan (90° – 2°)}….. {tan 44° tan (90° – 44°)} tan 45°
= (tan 1° cot 1°) (tan 2° cot 2°)…. (tan 44° cot 44°) tan45°
= (1) (1)…(1)(1) = 1
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
If f(x) = cos² x + sec ² x, then
Choice (a) is correct. Given that, f(x) = cos² x + sec² x We know that, A.M ≥ G.M (cos² x + sec ² x)/2 ≥ √cos² x. sec ² x ⇒ cos² x + sec ² x ≥ 2 ⇒ f(x) ≥ 2 This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understaRead more
Choice (a) is correct.
Given that, f(x) = cos² x + sec² x
We know that, A.M ≥ G.M
(cos² x + sec ² x)/2 ≥ √cos² x. sec ² x
⇒ cos² x + sec ² x ≥ 2
⇒ f(x) ≥ 2
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3
The value of cos 25° 35′ cos34° 25′ – sin 25° 34′ sin 34°’ 25′ is
Choice (d) is correct. cos 25° 35' cos 34° 25' - sin25° 35' sin 34°' 25' = cos(25° 35' + 34° 25') = cos 60° = 1/2 This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://wRead more
Choice (d) is correct.
cos 25° 35′ cos 34° 25′ – sin25° 35′ sin 34°’ 25′ = cos(25° 35′ + 34° 25′) = cos 60° = 1/2
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3
Period of cosecant function is
Choice (a) is correct. Period of cosecant function 2π. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chaptRead more
Choice (a) is correct.
Period of cosecant function 2π. This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3
The value of 64 π is
Choice (c) is correct. sin 64 π = sin (2π × 32 + 0) = sin 0 = 0 This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/matRead more
Choice (c) is correct.
sin 64 π = sin (2π × 32 + 0) = sin 0 = 0
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3
The value of tan 1° tan 2° tan 3° ….. tan89° is equal to
Choice (b) is correct tan 1° tan 2° tan 3° ..... tan89° = (tan 1° tan89°) (tan 2° tan 88°)....(tan 44° tan 46°) tan 45° = {tan 1° tan (90° - 1°)} {tan 2° tan (90° - 2°)}..... {tan 44° tan (90° - 44°)} tan 45° = (tan 1° cot 1°) (tan 2° cot 2°).... (tan 44° cot 44°) tan45° = (1) (1)...(1)(1) = 1 ThisRead more
Choice (b) is correct tan 1° tan 2° tan 3° ….. tan89° = (tan 1° tan89°) (tan 2° tan 88°)….(tan 44° tan 46°) tan 45°
= {tan 1° tan (90° – 1°)} {tan 2° tan (90° – 2°)}….. {tan 44° tan (90° – 44°)} tan 45°
= (tan 1° cot 1°) (tan 2° cot 2°)…. (tan 44° cot 44°) tan45°
= (1) (1)…(1)(1) = 1
This question related to Chapter 3 maths Class 11th NCERT. From the Chapter 3: Trigonometric Functions. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-3