Compound Chemical formula Elements present Quick lime CaO Calcium, oxygen Hydrogen bromide HBr Hydrogen, bromine Baking powder NaHCO3 Sodium, hydrogen, carbon, oxygen Potassium sulphate K2SO4 Potassium, sulphur, oxygen For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/Read more
Compound Chemical formula Elements present
Quick lime CaO Calcium, oxygen
Hydrogen bromide HBr Hydrogen, bromine
Baking powder NaHCO3 Sodium, hydrogen, carbon, oxygen
Potassium sulphate K2SO4 Potassium, sulphur, oxygen
A polyatomic ion is a group of atoms carrying a charge (positive or negative). For example, ammonium ion (𝑁𝐻+/4), hydroxide ion (OH−), carbonate ion (𝐶𝑂2/3−), sulphateion (𝑆𝑂2/4−). For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/
A polyatomic ion is a group of atoms carrying a charge (positive or negative). For example, ammonium ion (𝑁𝐻+/4), hydroxide ion (OH−), carbonate ion (𝐶𝑂2/3−), sulphateion (𝑆𝑂2/4−).
Carbon + Oxygen → Carbon dioxide 3g of carbon reacts with 8 g of oxygen to produce 11g of carbon dioxide. If 3g of carbon is burnt in 50g of oxygen, then 3g of carbon will react with 8 g of oxygen. The remaining 42 g of oxygen will be left un-reactive. In this case also, only 11g of carbon dioxide wRead more
Carbon + Oxygen → Carbon dioxide
3g of carbon reacts with 8 g of oxygen to produce 11g of carbon dioxide. If 3g of carbon is burnt in 50g of oxygen, then 3g of carbon will react with 8 g of oxygen. The remaining 42 g of oxygen will be left un-reactive. In this case also, only 11g of carbon dioxide will be formed. The above answer is governed by the law of constant proportions.
Mass of boron = 0.096g (Given) Mass of oxygen = 0.144g (Given) Mass of sample = 0.24g (Given) Thus, percentage of boron by weight in the compound = 0.096×1000. / 24% = 40% Thus, percentage of oxygen by weight in the compound = 0.144×1000./24% = 60 % For more answers visit to website: https://www.tiwRead more
Mass of boron = 0.096g (Given)
Mass of oxygen = 0.144g (Given)
Mass of sample = 0.24g (Given)
Thus, percentage of boron by weight in the compound = 0.096×1000. / 24% = 40%
Thus, percentage of oxygen by weight in the compound = 0.144×1000./24%
= 60 %
Give the names of the elements present in the following compounds.
Compound Chemical formula Elements present Quick lime CaO Calcium, oxygen Hydrogen bromide HBr Hydrogen, bromine Baking powder NaHCO3 Sodium, hydrogen, carbon, oxygen Potassium sulphate K2SO4 Potassium, sulphur, oxygen For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/Read more
Compound Chemical formula Elements present
Quick lime CaO Calcium, oxygen
Hydrogen bromide HBr Hydrogen, bromine
Baking powder NaHCO3 Sodium, hydrogen, carbon, oxygen
Potassium sulphate K2SO4 Potassium, sulphur, oxygen
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/
Write the chemical formulae of the following.
(a) Magnesium chloride →MgCl2 (b) Calcium oxide →CaO (c) Copper nitrate →Cu(NO3)2 (d) Aluminium chloride →AlCl3 (e) Calcium carbonate →CaCO3 For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/
(a) Magnesium chloride →MgCl2
(b) Calcium oxide →CaO
(c) Copper nitrate →Cu(NO3)2
(d) Aluminium chloride →AlCl3
(e) Calcium carbonate →CaCO3
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/
What are polyatomic ions? Give examples.
A polyatomic ion is a group of atoms carrying a charge (positive or negative). For example, ammonium ion (𝑁𝐻+/4), hydroxide ion (OH−), carbonate ion (𝐶𝑂2/3−), sulphateion (𝑆𝑂2/4−). For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/
A polyatomic ion is a group of atoms carrying a charge (positive or negative). For example, ammonium ion (𝑁𝐻+/4), hydroxide ion (OH−), carbonate ion (𝐶𝑂2/3−), sulphateion (𝑆𝑂2/4−).
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/
When 3.0 g of carbon is burnt in 8.00 g oxygen, 11.00 g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00 g of carbon is burnt in 50.00 g of oxygen? Which law of chemical combination will govern your answer?
Carbon + Oxygen → Carbon dioxide 3g of carbon reacts with 8 g of oxygen to produce 11g of carbon dioxide. If 3g of carbon is burnt in 50g of oxygen, then 3g of carbon will react with 8 g of oxygen. The remaining 42 g of oxygen will be left un-reactive. In this case also, only 11g of carbon dioxide wRead more
Carbon + Oxygen → Carbon dioxide
3g of carbon reacts with 8 g of oxygen to produce 11g of carbon dioxide. If 3g of carbon is burnt in 50g of oxygen, then 3g of carbon will react with 8 g of oxygen. The remaining 42 g of oxygen will be left un-reactive. In this case also, only 11g of carbon dioxide will be formed. The above answer is governed by the law of constant proportions.
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/
A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Mass of boron = 0.096g (Given) Mass of oxygen = 0.144g (Given) Mass of sample = 0.24g (Given) Thus, percentage of boron by weight in the compound = 0.096×1000. / 24% = 40% Thus, percentage of oxygen by weight in the compound = 0.144×1000./24% = 60 % For more answers visit to website: https://www.tiwRead more
Mass of boron = 0.096g (Given)
Mass of oxygen = 0.144g (Given)
Mass of sample = 0.24g (Given)
Thus, percentage of boron by weight in the compound = 0.096×1000. / 24% = 40%
Thus, percentage of oxygen by weight in the compound = 0.144×1000./24%
= 60 %
For more answers visit to website:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-3/