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  1. Asked: October 30, 2020In: Class 9

    Write the electronic configuration of any one pair of isotopes and isobars.

    Chemistry teacher
    Added an answer on December 13, 2020 at 6:14 am

    Two isotopes of carbon are ¹²₆𝐶 and ¹⁴₆𝐶 The electronic configuration of ¹²₆𝐶 is 2, 4. The electronic configuration of ¹⁴₆𝐶 is 2, 4. [Isotopes have same electronic configuration] ⁴⁰₂₉𝐶𝑎 and ⁴⁰₁₈𝐴𝑟 are a pair of isobars The electronic configuration of ⁴⁰₂₉𝐶𝑎 is 2, 8, 8, 2 The electronic configurationRead more

    Two isotopes of carbon are ¹²₆𝐶 and ¹⁴₆𝐶

    The electronic configuration of ¹²₆𝐶 is 2, 4.
    The electronic configuration of ¹⁴₆𝐶 is 2, 4.
    [Isotopes have same electronic configuration]
    ⁴⁰₂₉𝐶𝑎 and ⁴⁰₁₈𝐴𝑟 are a pair of isobars
    The electronic configuration of ⁴⁰₂₉𝐶𝑎 is 2, 8, 8, 2
    The electronic configuration of ⁴⁰₁₈𝐴𝑟 is 2, 8, 8.
    [Isobars have different electronic configuration]

    For more answers visit to website:
    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-4/

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  2. Asked: October 30, 2020In: Class 9

    For the symbol H,D and T tabulate three sub-atomic particles found in each of them.

    Chemistry teacher
    Added an answer on December 13, 2020 at 6:07 am

    Symbol Proton Neutron Electron H 1 0 1 D 1 1 1 For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-4/

    Symbol Proton Neutron Electron
    H 1 0 1
    D 1 1 1

    For more answers visit to website:
    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-4/

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  3. Asked: October 30, 2020In: Class 9

    With the help of Table 4.1, find out the mass number of oxygen and Sulphur atom.

    Chemistry teacher
    Added an answer on December 13, 2020 at 6:03 am

    Mass number of oxygen = Number of protons + Number of neutrons = 8 + 8 = 16 Mass number of sulphur = Number of protons + Number of neutrons = 16 +16 = 32 For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-4/

    Mass number of oxygen = Number of protons + Number of neutrons
    = 8 + 8
    = 16
    Mass number of sulphur = Number of protons + Number of neutrons
    = 16 +16
    = 32

    For more answers visit to website:
    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-4/

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  4. Asked: October 28, 2020In: Class 9

    If number of electrons in an atom is 8 and number of protons is also 8, then (i) what is the atomic number of the atom? and (ii) what is the charge on the atom?

    Chemistry teacher
    Added an answer on December 13, 2020 at 6:02 am

    (i) The atomic number is equal to the number of protons. Therefore, the atomic number of the atom is 8. (ii) Since the number of both electrons and protons is equal, therefore, the charge on the atom is 0. For more answers visit to website: https://www.tiwariacademy.com/ncert-solutions/class-9/scienRead more

    (i) The atomic number is equal to the number of protons. Therefore, the atomic number of
    the atom is 8.
    (ii) Since the number of both electrons and protons is equal, therefore, the charge on the
    atom is 0.

    For more answers visit to website:
    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-4/

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  5. Asked: October 28, 2020In: Class 9

    How will you find the valency of chlorine, Sulphur and magnesium?

    Chemistry teacher
    Added an answer on December 13, 2020 at 6:01 am

    If the number of electrons in the outermost shell of the atom of an element is less than or equal to 4, then the valency of the element is equal to the number of electrons in the outermost shell. On the other hand, if the number of electrons in the outermost shell of the atom of an element is greateRead more

    If the number of electrons in the outermost shell of the atom of an element is less than or equal to
    4, then the valency of the element is equal to the number of electrons in the outermost shell.
    On the other hand, if the number of electrons in the outermost shell of the atom of an element is greater than 4, then the valency of that element is determined by subtracting the number of electrons in the outermost shell from 8.
    The distribution of electrons in chlorine, sulphur, and magnesium atoms are 2, 8, 7; 2, 8, 6 and 2, 8, 2 respectively. Therefore, the number of electrons in the outer most shell of chlorine, sulphur, and magnesium atoms are 7, 6, and 2 respectively.
    Thus,
    The valency of chlorine = 8 −7 = 1
    The valency of sulphur = 8 − 6 = 2
    The valency of magnesium = 2

    For more answers visit to website:
    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-4/

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