What's your question?
  1. Microwaves are suitable for radar systems in aircraft navigation due to their short wavelength, allowing precise detection of objects, high penetration through clouds and fog, and efficient reflection from metallic surfaces for accurate location and distance measurement. For more visit here: https:/Read more

    Microwaves are suitable for radar systems in aircraft navigation due to their short wavelength, allowing precise detection of objects, high penetration through clouds and fog, and efficient reflection from metallic surfaces for accurate location and distance measurement.

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-8/

    See less
    • 2
  2. The escape velocity of a celestial body is the minimum speed required for an object to break free from its gravitational influence without any further propulsion. For a planet with a mass equal to that of Earth but with a radius that is one-fourth of Earth's radius, the escape velocity is much higheRead more

    The escape velocity of a celestial body is the minimum speed required for an object to break free from its gravitational influence without any further propulsion. For a planet with a mass equal to that of Earth but with a radius that is one-fourth of Earth’s radius, the escape velocity is much higher than that of Earth.

    This is due to the relation between mass and radius in gravitational physics. The gravitational pull an object experiences on the surface of the planet depends on both the mass of the planet and the distance from its center. As the radius is reduced to one-fourth, the gravitational force at the surface increases, and it needs a greater speed to escape the gravitational field of the planet.

    This means that the escape velocity for this hypothetical planet is about 22.4 km/s, which is double the escape velocity of Earth, which is about 11.2 km/s. This means that an object launched from the surface of this planet must achieve a much higher speed to overcome the stronger gravitational attraction. Understanding this concept is crucial for space missions and exploring the dynamics of celestial bodies in our universe.

    See less
    • 4
  3. (i) A wave with a frequency of 3 × 10¹⁹ Hz belongs to the X-ray region of the electromagnetic spectrum. (ii) A wave with 5 × 10¹¹ Hz frequency belongs to the microwave region. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-8/

    (i) A wave with a frequency of 3 × 10¹⁹ Hz belongs to the X-ray region of the electromagnetic spectrum.
    (ii) A wave with 5 × 10¹¹ Hz frequency belongs to the microwave region.

    For more visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-8/

    See less
    • 2
  4. When a planet revolves in an elliptical orbit around the sun, a variety of energies and angular momentums are involved. The total energy, E in this context, is thus very important since it stands for the sum of kinetic energy T and gravitational potential energy V of the planet. In any bound elliptiRead more

    When a planet revolves in an elliptical orbit around the sun, a variety of energies and angular momentums are involved. The total energy, E in this context, is thus very important since it stands for the sum of kinetic energy T and gravitational potential energy V of the planet.

    In any bound elliptical orbit of a planet, total energy is always negative. This negative value means that the planet is gravitationally bound to the sun, with insufficient energy to leave the influence of the gravitational pull from the sun. The reason why the gravitational potential energy is negative is because of the attraction caused by gravity; the more negative this energy gets as the planet approaches the sun, the greater is its kinetic energy, which peaks at periapsis, the closest point of the orbit to the sun.

    On the other hand, at apoapsis, where the planet is farthest from the sun, its kinetic energy is lower, but the gravitational potential energy is still negative. The total energy is consistently negative, and this is what reflects the stability of the orbit. Therefore, it is evident that for a planet in an elliptical orbit, the total energy is always negative, which is a further proof of the concept of gravitational binding in celestial mechanics.

    See less
    • 4
  5. The period of revolution of a planet from the Sun is related to its distance from the Sun by Kepler's third law. This law explains that the square of the orbital period of a planet is proportional to the cube of its average distance from the Sun. Here, planet A takes 8 times longer to complete one rRead more

    The period of revolution of a planet from the Sun is related to its distance from the Sun by Kepler’s third law. This law explains that the square of the orbital period of a planet is proportional to the cube of its average distance from the Sun. Here, planet A takes 8 times longer to complete one revolution around the Sun as compared to planet B.

    Using Kepler’s law, the relationship between the orbital period and distance implies that if the period of revolution of planet A is 8 times that of planet B, the cube root of the square of this ratio will give the ratio of their distances from the Sun. Simplifying this relationship, it is determined that the distance of planet A from the Sun is 4 times greater than that of planet B.

    This result demonstrates how much more time is taken by the planet to complete its orbit as the distance from the Sun increases. The universality of this principle among all celestial bodies that move in elliptical orbits tells us a lot about planetary systems’ structure and dynamics, bringing to light harmony between orbital period and distance in celestial mechanics.

    See less
    • 3