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Mercury thermometer can be used to measure temperature upto
Mercury thermometers can measure temperatures up to around 360°C because mercury stays in its liquid state up to this temperature. Beyond this, mercury begins to vaporize and cannot be used for measurements above this point. Click for more: https://www.tiwariacademy.com/ncert-solutions/class-11/physRead more
Mercury thermometers can measure temperatures up to around 360°C because mercury stays in its liquid state up to this temperature. Beyond this, mercury begins to vaporize and cannot be used for measurements above this point.
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If the temperature of the sun were to increase from T to 2 T and its radius from R to 2 R, then the ratio of the radiant energy received on earth to what it was previously, will be
The amount of sun's radiant energy received is proportional to the power output of the sun from Stefan-Boltzmann's Law: P ∝ R²T⁴ 1. Preliminary P₁ ∝ R²T⁴ 2. After alteration - The radius increases to 2R: The area increases proportionally to (2R)² = 4R² - Temperature increases to 2T: Power increasesRead more
The amount of sun’s radiant energy received is proportional to the power output of the sun from Stefan-Boltzmann’s Law:
P ∝ R²T⁴
1. Preliminary
P₁ ∝ R²T⁴
2. After alteration
– The radius increases to 2R: The area increases proportionally to (2R)² = 4R²
– Temperature increases to 2T: Power increases proportionally to (2T)⁴ = 16T⁴
– Total power increases to:
P₂ ∝ 4R² × 16T⁴ = 64R²T⁴
3. The ratio of the new power to the old power:
P₂ / P₁ = (64R²T⁴) / (R²T⁴) = 64
Thus, the radiant energy received on Earth will increase by a factor of 64.
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What did you enjoy doing?
I enjoyed the hands-on experience of planting seeds, nurturing them with care, and witnessing their growth. Watering the plants and maintaining the garden offered a sense of responsibility and satisfaction. The highlight was harvesting fresh produce, which was a rewarding outcome of the effort. AddiRead more
I enjoyed the hands-on experience of planting seeds, nurturing them with care, and witnessing their growth. Watering the plants and maintaining the garden offered a sense of responsibility and satisfaction. The highlight was harvesting fresh produce, which was a rewarding outcome of the effort. Additionally, designing the garden layout, arranging pots, and adding decorative elements enhanced the joy of the activity, making it both educational and creatively fulfilling.
See lessFor measuring temperature in the range of 2,000 to 2,500°C, we should employ
Pyrometers are designed to measure extremely high temperatures, such as those in the range of 2,000 to 2,500°C, and are commonly used in industrial applications like furnaces and molten metal. Click here for more: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-10/
Pyrometers are designed to measure extremely high temperatures, such as those in the range of 2,000 to 2,500°C, and are commonly used in industrial applications like furnaces and molten metal.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-10/
Heat is flowing through the cylindrical rods of the same material. The diameter of the rods are in the ratio 1 : 2 and their lengths are in the ratio 2 : 1. If the temperature difference between their ends is the same, them the ratio of the amount of heat conducted through them per unit time will be
We apply the formula for heat conduction rate to solve this. Q = (kA(T₂ - T₁)) / L Q is the heat conducted per unit time k is the thermal conductivity A is the cross-sectional area (T₂ - T₁) is the temperature difference L is the length of the rod. We are given - The diameters are in the ratio 1:2,Read more
We apply the formula for heat conduction rate to solve this.
Q = (kA(T₂ – T₁)) / L
Q is the heat conducted per unit time
k is the thermal conductivity
A is the cross-sectional area
(T₂ – T₁) is the temperature difference
L is the length of the rod.
We are given
– The diameters are in the ratio 1:2, so the areas A will be in the ratio 1² : 2² = 1:4,
– The lengths are in the ratio 2:1.
We can now compute the ratio of heat conducted through the rods:
(Q₁ / Q₂) = (A₁ / L₁) × (L₂ / A₂) = (1 / 2) × (4 / 1) = 2
Thus, the ratio of heat conducted through the rods per unit time is 2:1.
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