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What will be the formula and electron dot structure of cyclopentane?

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NCERT Solution for Class Tenth Science Chapter 4
Carbon and its Compounds
CBSE NCERT Book Session-2022-2023
Intext Questions
Page No-11
Questions No-3

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  1. Cyclopentane is a cyclic hydrocarbon with the molecular formula C₅H₁₀. It consists of a ring of five carbon atoms, each bonded to two hydrogen atoms. The electron dot structure (Lewis structure) of cyclopentane can be determined by following these steps:

    1. Determine the Total Valence Electrons:

    » Each carbon contributes 4 valence electrons, and each hydrogen contributes 1 valence electron.

    » Total valence electrons for C₅H₁₀ = 5 × 4 +10 × 1= 30 electrons.

    2. Arrange Atoms in a Ring:

    . Arrange the five carbon atoms in a ring.

    3. Connect Atoms with Single Bonds:

    » Form single bonds between each carbon atom and its adjacent carbon atoms to create the cyclopentane ring.

    4. Distribute Remaining Electrons:

    » Distribute the remaining electrons around the carbon atoms to satisfy the octet rule.

    5. Check for Octet Rule:

    » Ensure that each carbon atom in the ring has a full outer shell of 8 electrons.

    The electron dot structure for cyclopentane (C₅H₁₀) is as follows:

    H H
    \ /
    C─C─C─C─C
    /
    H

    In this structure, each carbon atom is bonded to two hydrogen atoms, and the carbon atoms are connected by single bonds in a cyclical arrangement. The octet rule is satisfied for each carbon atom in the cyclopentane ring.

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  2. Get Hindi Medium and English Medium NCERT Solution for Class 10 Science to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-10/science/chapter-4/

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